Unit D.2: Electric and Magnetic Fields单元 D.2:电场与磁场
Part of Theme D "Fields". Electric charge, conductors and insulators, Coulomb's law, electric field strength and field-line patterns, the uniform field between parallel plates, and the magnetic-field patterns of bar magnets, current-carrying wires and solenoids. The HL extension introduces electric potential and electric potential energy, equipotentials, and the field-potential link. The unit closes by comparing gravitational, electric and magnetic fields in one synthesis table. This material is the foundation for D.3 (motion in EM fields) and D.4 (induction).主题 D"场"的一部分。电荷、导体与绝缘体、库仑定律、电场强度与电场线图样、平行板间的匀强电场,以及条形磁铁、载流导线与螺线管的磁场图样。HL 扩展引入电势、电势能、等势面以及场-势之间的关系。本单元以一张综合表对比引力场、电场与磁场作结。这些内容是 D.3(电磁场中的运动)与 D.4(电磁感应)的基础。
How to use this guide本指南使用说明
D.2 is built on one idea repeated three ways: a source creates a field, and the field exerts a force on whatever you place in it. Master the parallel structure — Coulomb force vs field strength, point-charge field vs uniform field, electric vs magnetic — and most marks fall out of substitution. The arithmetic uses powers of ten ($k = 8.99 \times 10^{9}$, charges in $\mathrm{nC}$ or $\mu\mathrm{C}$), so train your calculator discipline alongside the physics.D.2 的核心是同一思想的三种表述:源产生场,场对放入其中的物体施力。掌握这种平行结构——库仑力与电场强度、点电荷场与匀强场、电场与磁场——大多数分数都来自代入计算。运算涉及 10 的幂次($k = 8.99 \times 10^{9}$,电荷常以 $\mathrm{nC}$ 或 $\mu\mathrm{C}$ 计),因此物理与计算器规范要一起练。
Memorise three force/field equations: Coulomb's law $F = \dfrac{k q_1 q_2}{r^2}$, field of a point charge $E = \dfrac{kQ}{r^2}$, and the uniform-plate field $E = \dfrac{V}{d}$ with $F = qE$. Field lines: out of positive, into negative, never crossing. Magnetic field: north to south outside a magnet; right-hand grip rule for a wire.
背熟三条力/场公式:库仑定律 $F = \dfrac{k q_1 q_2}{r^2}$、点电荷场 $E = \dfrac{kQ}{r^2}$、平行板匀强场 $E = \dfrac{V}{d}$ 且 $F = qE$。电场线:出正入负、永不相交。磁场:磁铁外部由北指向南;导线用右手螺旋定则。
Be fluent moving between field and potential HL: $V_e = \dfrac{kQ}{r}$, $E_p = \dfrac{k q_1 q_2}{r}$, equipotentials perpendicular to field lines, and $W = q \Delta V_e$. Know why the electric force can be attractive or repulsive while gravity is only attractive, and why magnetic field lines form closed loops with no monopole source. Sketch dipole and solenoid patterns from memory.
能在场与势之间自如转换 HL:$V_e = \dfrac{kQ}{r}$、$E_p = \dfrac{k q_1 q_2}{r}$、等势面垂直于电场线、$W = q \Delta V_e$。理解为何电力可吸可斥而引力只能吸引,以及磁感线为何是无磁单极源的闭合回路。能默画偶极子与螺线管的场图样。
Electric Charge, Conductors & Insulators, Coulomb's Law电荷、导体与绝缘体、库仑定律 D.2 SL+HL
- Charge $q$ is quantised in units of $e = 1.60 \times 10^{-19}\ \mathrm{C}$; like charges repel, unlike attract.
- Conductor: free charge carriers (electrons in metals) move easily. Insulator: charges are bound and do not flow.
- Charge is conserved: it is transferred (friction, contact, induction), never created or destroyed.
F = kq₁q₂ / r²:
$$ F = \frac{k q_1 q_2}{r^2}, \qquad k = \frac{1}{4\pi\varepsilon_0} = 8.99 \times 10^{9}\ \mathrm{N\,m^2\,C^{-2}}. $$
Sign rule. A positive product $q_1 q_2 > 0$ means repulsion; negative means attraction. Always state the direction separately from the magnitude.
- 电荷(charge)$q$ 以 $e = 1.60 \times 10^{-19}\ \mathrm{C}$ 为单位量子化;同号相斥、异号相吸。
- 导体(conductor):自由载流子(金属中的电子)易于移动。绝缘体(insulator):电荷被束缚,不能流动。
- 电荷守恒:只能转移(摩擦、接触、感应),不能凭空产生或消失。
F = kq₁q₂ / r²:
$$ F = \frac{k q_1 q_2}{r^2}, \qquad k = \frac{1}{4\pi\varepsilon_0} = 8.99 \times 10^{9}\ \mathrm{N\,m^2\,C^{-2}}. $$
符号规则。乘积 $q_1 q_2 > 0$ 表示相斥;为负表示相吸。方向要与大小分开说明。
Two point charges $q_1 = +3.0\ \mathrm{nC}$ and $q_2 = -5.0\ \mathrm{nC}$ are separated by $4.0\ \mathrm{cm}$ in vacuum. Find the magnitude and nature of the electrostatic force between them.真空中两点电荷 $q_1 = +3.0\ \mathrm{nC}$ 与 $q_2 = -5.0\ \mathrm{nC}$ 相距 $4.0\ \mathrm{cm}$。求它们之间静电力的大小与性质。
Identify. Coulomb's law with $k = 8.99 \times 10^{9}$, $r = 0.040\ \mathrm{m}$. Convert charges: $3.0\ \mathrm{nC} = 3.0 \times 10^{-9}\ \mathrm{C}$, $5.0\ \mathrm{nC} = 5.0 \times 10^{-9}\ \mathrm{C}$.
识别。用库仑定律,$k = 8.99 \times 10^{9}$、$r = 0.040\ \mathrm{m}$。换算电荷:$3.0\ \mathrm{nC} = 3.0 \times 10^{-9}\ \mathrm{C}$、$5.0\ \mathrm{nC} = 5.0 \times 10^{-9}\ \mathrm{C}$。
Substitute (use magnitudes for the size):
代入(用电荷大小求力的大小):
$$ F = \frac{(8.99 \times 10^{9})(3.0 \times 10^{-9})(5.0 \times 10^{-9})}{(0.040)^2}. $$ $$ F = \frac{8.99 \times 10^{9} \times 1.5 \times 10^{-17}}{1.6 \times 10^{-3}} \approx 8.4 \times 10^{-5}\ \mathrm{N}. $$Evaluate. Magnitude $\approx 8.4 \times 10^{-5}\ \mathrm{N}$. Since the charges are unlike, the force is attractive — each charge is pulled toward the other along the line joining them.
评估。大小约 $8.4 \times 10^{-5}\ \mathrm{N}$。两电荷异号,故为吸引力——沿连线相互拉近。
Going deeper: the inverse-square law and superposition深入:平方反比与叠加原理
Coulomb's law is an inverse-square law: doubling $r$ quarters the force. This shares its mathematical form with Newton's law of gravitation $F = \dfrac{G m_1 m_2}{r^2}$ — a parallel we exploit in D2.6.
库仑定律是平方反比律:$r$ 加倍,力变为四分之一。它与牛顿万有引力 $F = \dfrac{G m_1 m_2}{r^2}$ 形式相同——这一平行关系将在 D2.6 中利用。
For more than two charges, the net force on any one charge is the vector sum of the individual Coulomb forces (superposition). Resolve each pairwise force into components, add component-wise, then recombine. The constant can be written either as $k$ or via the permittivity of free space $\varepsilon_0 = 8.85 \times 10^{-12}\ \mathrm{C^2\,N^{-1}\,m^{-2}}$, since $k = \dfrac{1}{4\pi\varepsilon_0}$.
超过两个电荷时,某电荷所受合力是各对库仑力的矢量和(叠加原理)。把每对力分解为分量、按分量相加、再合成。常数可写为 $k$,也可用真空介电常数 $\varepsilon_0 = 8.85 \times 10^{-12}\ \mathrm{C^2\,N^{-1}\,m^{-2}}$,因为 $k = \dfrac{1}{4\pi\varepsilon_0}$。
Electric Field Strength and Field-Line Patterns电场强度与电场线图样 D.2 SL+HL
E = F / q:
$$ E = \frac{F}{q}, \qquad E = \frac{kQ}{r^2}\ \text{(radial, point charge $Q$)}. $$
Units $\mathrm{N\,C^{-1}}$ (equivalently $\mathrm{V\,m^{-1}}$). $E$ is a vector pointing in the direction of the force on a positive charge.
Field-line rules.
- Lines point out of positive charges, into negative charges.
- Density of lines $\propto$ field strength; lines never cross.
- Point charge: radial lines. Dipole ($+$ and $-$): lines curve from $+$ to $-$.
E = F / q:
$$ E = \frac{F}{q}, \qquad E = \frac{kQ}{r^2}\ \text{(点电荷 $Q$ 的径向场)}. $$
单位 $\mathrm{N\,C^{-1}}$(等价于 $\mathrm{V\,m^{-1}}$)。$E$ 是矢量,指向正电荷所受力的方向。
电场线规则。
- 电场线从正电荷发出,在负电荷终止。
- 线的疏密 $\propto$ 场强;电场线永不相交。
- 点电荷:径向线。偶极子($+$ 与 $-$):线从 $+$ 弯向 $-$。
A point charge $Q = +6.0\ \mathrm{nC}$ sits in vacuum. (a) Find the electric field strength at $r = 0.20\ \mathrm{m}$. (b) Find the force on a test charge $q = -2.0\ \mathrm{nC}$ placed there.真空中有点电荷 $Q = +6.0\ \mathrm{nC}$。(a) 求 $r = 0.20\ \mathrm{m}$ 处的电场强度。(b) 求放在该处的检验电荷 $q = -2.0\ \mathrm{nC}$ 所受的力。
(a) Field strength. Radial point-charge field $E = \dfrac{kQ}{r^2}$:
(a) 场强。点电荷径向场 $E = \dfrac{kQ}{r^2}$:
$$ E = \frac{(8.99 \times 10^{9})(6.0 \times 10^{-9})}{(0.20)^2} = \frac{53.9}{0.040} \approx 1.35 \times 10^{3}\ \mathrm{N\,C^{-1}}. $$Direction: radially outward (away from the positive source).
方向:沿径向向外(背离正源)。
(b) Force on the test charge. Use $F = qE$ with magnitudes:
(b) 检验电荷受力。用 $F = qE$(取大小):
$$ F = qE = (2.0 \times 10^{-9})(1.35 \times 10^{3}) \approx 2.7 \times 10^{-6}\ \mathrm{N}. $$Evaluate. The test charge is negative, so the force is opposite to $E$ — directed radially inward, toward $Q$ (attraction). Magnitude $\approx 2.7\ \mu\mathrm{N}$.
评估。检验电荷为负,受力与 $E$ 相反——沿径向向内,指向 $Q$(吸引)。大小约 $2.7\ \mu\mathrm{N}$。
Going deeper: why field lines never cross, and reading dipole patterns深入:电场线为何不相交,以及读偶极子图样
At every point the field has a single, definite direction (the net force per unit charge there). If two field lines crossed, the field would have two directions at the crossing point — a contradiction. Hence lines never intersect.
每一点的场都有唯一确定的方向(该处单位电荷受到的合力)。若两条电场线相交,交点处的场将有两个方向——矛盾。因此电场线不相交。
For a dipole (equal $+$ and $-$ charges), lines leave the positive charge, curve through space, and enter the negative charge. Exactly midway on the perpendicular bisector the field is non-zero and points from $+$ toward $-$. Contrast with two like charges: there a null point (zero field) sits midway, and lines push apart rather than join.
对偶极子(等量 $+$ 与 $-$),电场线从正电荷发出、在空间弯曲、终止于负电荷。在中垂线正中点处场不为零,由 $+$ 指向 $-$。与两个同号电荷对比:那里中点是零场点,电场线互相排开而非相连。
Uniform Electric Field Between Parallel Plates平行板间的匀强电场 D.2 SL+HL
E = V / d:
$$ E = \frac{V}{d}, \qquad F = qE = \frac{qV}{d}. $$
Key features.
- Field lines are straight, parallel, equally spaced, from the $+$ plate to the $-$ plate.
- The force on a charge is the same everywhere between the plates — analogous to gravity near Earth's surface.
- Edge effects (fringing) are ignored at the IB level.
E = V / d:
$$ E = \frac{V}{d}, \qquad F = qE = \frac{qV}{d}. $$
关键特征。
- 电场线笔直、平行、等间距,从 $+$ 板指向 $-$ 板。
- 板间各处对电荷的力处处相同——类比地表附近的重力。
- IB 层面忽略边缘效应(边缘发散)。
Two horizontal parallel plates are separated by $d = 2.0\ \mathrm{cm}$ and connected to a $V = 300\ \mathrm{V}$ supply. (a) Find the field strength between them. (b) Find the force on an oil droplet carrying charge $q = 3.2 \times 10^{-19}\ \mathrm{C}$ (two electron charges).两水平平行板相距 $d = 2.0\ \mathrm{cm}$,接 $V = 300\ \mathrm{V}$ 电源。(a) 求板间场强。(b) 求带电 $q = 3.2 \times 10^{-19}\ \mathrm{C}$(两个电子电荷)的油滴所受的力。
(a) Field strength. $E = \dfrac{V}{d}$ with $d = 0.020\ \mathrm{m}$:
(a) 场强。$E = \dfrac{V}{d}$,$d = 0.020\ \mathrm{m}$:
$$ E = \frac{300}{0.020} = 1.5 \times 10^{4}\ \mathrm{V\,m^{-1}}. $$(b) Force. $F = qE$:
(b) 受力。$F = qE$:
$$ F = (3.2 \times 10^{-19})(1.5 \times 10^{4}) \approx 4.8 \times 10^{-15}\ \mathrm{N}. $$Evaluate. The force has the same value anywhere between the plates because the field is uniform. This is the principle behind Millikan's oil-drop experiment, where this electric force is balanced against the droplet's weight.
评估。因场为匀强,板间各处受力相同。这正是密立根油滴实验的原理:用此电力平衡油滴重力。
Going deeper: why $\mathrm{N\,C^{-1}}$ and $\mathrm{V\,m^{-1}}$ are the same unit深入:为何 $\mathrm{N\,C^{-1}}$ 与 $\mathrm{V\,m^{-1}}$是同一单位
From $E = V/d$, the field has units $\mathrm{V\,m^{-1}}$. From $E = F/q$, it has units $\mathrm{N\,C^{-1}}$. These are identical because $1\ \mathrm{V} = 1\ \mathrm{J\,C^{-1}}$ and $1\ \mathrm{J} = 1\ \mathrm{N\,m}$:
由 $E = V/d$,场的单位为 $\mathrm{V\,m^{-1}}$。由 $E = F/q$,单位为 $\mathrm{N\,C^{-1}}$。二者相同,因为 $1\ \mathrm{V} = 1\ \mathrm{J\,C^{-1}}$ 且 $1\ \mathrm{J} = 1\ \mathrm{N\,m}$:
$$ \frac{\mathrm{V}}{\mathrm{m}} = \frac{\mathrm{J\,C^{-1}}}{\mathrm{m}} = \frac{\mathrm{N\,m\,C^{-1}}}{\mathrm{m}} = \mathrm{N\,C^{-1}}. $$A charged particle entering a uniform field perpendicular to the field lines follows a parabolic path, exactly like a projectile in gravity: constant velocity along the plates, constant acceleration $a = qE/m$ across them. That trajectory analysis is developed in D.3.
带电粒子垂直于电场线进入匀强场后走抛物线,与重力中的抛体完全类似:沿板方向匀速,垂直方向匀加速 $a = qE/m$。该轨迹分析在 D.3 展开。
Electric Potential and Electric Potential Energy电势与电势能 HL D.2 HL
Vₑ = kQ / r:
$$ V_e = \frac{kQ}{r} \quad (\mathrm{V} = \mathrm{J\,C^{-1}}). $$
Electric potential energy (HL). Of a pair of point charges, from the data booklet Eₚ = kq₁q₂ / r:
$$ E_p = \frac{k q_1 q_2}{r} = q V_e. $$
Work done (HL). Moving charge $q$ between two points: $W = q\,\Delta V_e$.
Equipotentials. Surfaces of constant $V_e$; always perpendicular to field lines. No work is done moving a charge along an equipotential.
Vₑ = kQ / r:
$$ V_e = \frac{kQ}{r} \quad (\mathrm{V} = \mathrm{J\,C^{-1}}). $$
电势能(HL)。一对点电荷的电势能,数据手册中 Eₚ = kq₁q₂ / r:
$$ E_p = \frac{k q_1 q_2}{r} = q V_e. $$
所做的功(HL)。把电荷 $q$ 在两点间移动:$W = q\,\Delta V_e$。
等势面。$V_e$ 恒定的面;总与电场线垂直。沿等势面移动电荷不做功。
A point charge $Q = +4.0\ \mathrm{nC}$ is in vacuum. (a) Find the electric potential at $r_1 = 0.10\ \mathrm{m}$ and at $r_2 = 0.30\ \mathrm{m}$. (b) Find the work done by an external agent moving a charge $q = +2.0\ \mathrm{nC}$ from $r_2$ to $r_1$.真空中点电荷 $Q = +4.0\ \mathrm{nC}$。(a) 求 $r_1 = 0.10\ \mathrm{m}$ 与 $r_2 = 0.30\ \mathrm{m}$ 处的电势。(b) 求外力把电荷 $q = +2.0\ \mathrm{nC}$ 从 $r_2$ 移到 $r_1$ 所做的功。
(a) Potentials. $V_e = \dfrac{kQ}{r}$:
(a) 各处电势。$V_e = \dfrac{kQ}{r}$:
$$ V_1 = \frac{(8.99 \times 10^{9})(4.0 \times 10^{-9})}{0.10} \approx 360\ \mathrm{V}, $$ $$ V_2 = \frac{(8.99 \times 10^{9})(4.0 \times 10^{-9})}{0.30} \approx 120\ \mathrm{V}. $$(b) Work done. $W = q\,\Delta V_e = q (V_1 - V_2)$:
(b) 所做的功。$W = q\,\Delta V_e = q (V_1 - V_2)$:
$$ W = (2.0 \times 10^{-9})(360 - 120) = (2.0 \times 10^{-9})(240) \approx 4.8 \times 10^{-7}\ \mathrm{J}. $$Evaluate. Positive work is required: moving a positive charge toward a positive source raises its potential energy (pushing against repulsion). The agent does $\approx 0.48\ \mu\mathrm{J}$ on the charge.
评估。需做正功:把正电荷推向正源会升高其电势能(逆着斥力)。外力对电荷做功约 $0.48\ \mu\mathrm{J}$。
Going deeper: the field–potential link HL深入:场-势关系 HL
Electric field strength is the negative gradient of potential: the field points "downhill" in potential, from high $V_e$ to low $V_e$. For a uniform field this reduces to the relation you already met:
电场强度是电势的负梯度:场指向电势"下坡"方向,由高 $V_e$ 指向低 $V_e$。对匀强场,这退化为你已学过的关系:
$$ E = -\frac{\Delta V_e}{\Delta r}, \qquad \text{(uniform field)}\ E = \frac{V}{d}. $$On a diagram, equipotentials are like contour lines on a map and field lines are the steepest-descent paths crossing them at right angles. Closely spaced equipotentials mean a large $\Delta V_e$ over a small $\Delta r$, hence a strong field. Note the sign and distance contrast with PE: potential $V_e \propto 1/r$ falls off more slowly than field $E \propto 1/r^2$.
在图上,等势面如地图上的等高线,电场线则是与之处处垂直的最陡下降路径。等势面越密表示小 $\Delta r$ 上有大 $\Delta V_e$,即场越强。注意与场的距离差别:电势 $V_e \propto 1/r$ 比场 $E \propto 1/r^2$ 衰减更慢。
Magnetic Fields: Magnets, Wires and Solenoids磁场:磁铁、导线与螺线管 D.2 SL+HL
- Bar magnet: lines emerge from N, curve round, enter S; densest (strongest) at the poles.
- Long straight wire: concentric circles around the wire. Right-hand grip rule: thumb along the conventional current, fingers curl in the direction of $B$.
- Solenoid: uniform field inside (like a bar magnet's exterior), with N and S ends set by the grip rule applied to the coils.
- 条形磁铁:磁感线由 N 出、绕行、入 S;两极处最密(最强)。
- 长直导线:环绕导线的同心圆。右手螺旋定则:拇指沿常规电流方向,四指弯曲方向即 $B$ 的方向。
- 螺线管(solenoid):内部匀强场(如条形磁铁外部),N、S 端由对线圈用螺旋定则确定。
A long straight vertical wire carries conventional current upward (out of the floor toward the ceiling). Determine the direction of the magnetic field at a point due north of the wire, and at a point due east of it.一根长直竖直导线中常规电流向上(由地面指向天花板)。判断导线正北方某点与正东方某点处磁场的方向。
Identify. Use the right-hand grip rule: point the thumb upward (current direction); the fingers curl anticlockwise when viewed from above.
识别。用右手螺旋定则:拇指向上(电流方向);从上方看,四指逆时针弯曲。
North point. At a point north of the wire, the anticlockwise circulation (viewed from above) points the field toward the west.
正北点。在导线正北处,(俯视)逆时针环流使该点场指向正西。
East point. Continuing anticlockwise, at a point east of the wire the field points toward the north.
正东点。沿逆时针继续,在导线正东处场指向正北。
Evaluate. The field circulates in horizontal circles around the vertical wire, anticlockwise seen from above. Its magnitude falls with distance from the wire, so the circles are most tightly "felt" close in.
评估。场在竖直导线周围作水平圆周环流,俯视为逆时针。其大小随离导线距离增大而减小,故近处场最强。
Going deeper: why magnetic field lines are closed loops深入:磁感线为何是闭合回路
Electric field lines start and end on charges (sources and sinks). Magnetic field lines never start or stop — they always form complete closed loops. The deep reason is that no isolated magnetic "charge" (a monopole) has ever been found: cut a bar magnet in half and you get two smaller magnets, each with its own N and S.
电场线起止于电荷(源与汇)。磁感线既不起也不止——总是构成完整闭合回路。根本原因是从未发现孤立的磁"荷"(磁单极子):把条形磁铁切成两半会得到两块更小的磁铁,各自仍有 N、S 极。
Inside a solenoid, the loops from all the turns reinforce to give a nearly uniform interior field; outside, the return paths spread out and weaken, giving the solenoid the same external pattern as a bar magnet. This equivalence is why a current-carrying coil is an electromagnet, and reversing the current swaps its N and S ends.
在螺线管内部,各匝的回路相互增强,形成近乎匀强的内部场;外部,回路返回路径展开变弱,使螺线管外部图样与条形磁铁相同。正因这种等价,载流线圈即为电磁铁,反转电流即可互换其 N、S 端。
Comparing Gravitational, Electric and Magnetic Fields引力场、电场与磁场的对比 D.2 SL+HL
- Force: $F = \dfrac{G m_1 m_2}{r^2}$ vs $F = \dfrac{k q_1 q_2}{r^2}$.
- Field: $g = \dfrac{GM}{r^2}$ vs $E = \dfrac{kQ}{r^2}$.
- "Charge" of the field: mass $m$ (only positive) vs charge $q$ ($\pm$) vs there is no magnetic monopole.
- 力:$F = \dfrac{G m_1 m_2}{r^2}$ 与 $F = \dfrac{k q_1 q_2}{r^2}$。
- 场:$g = \dfrac{GM}{r^2}$ 与 $E = \dfrac{kQ}{r^2}$。
- 场的"荷":质量 $m$(只为正)与电荷 $q$($\pm$)与不存在磁单极子。
| Feature特征 | Gravitational引力场 | Electric电场 | Magnetic磁场 |
|---|---|---|---|
| Source源 | Mass $m$质量 $m$ | Charge $q$电荷 $q$ | Moving charge / magnet运动电荷 / 磁铁 |
| Sign of "charge""荷"的符号 | Positive only只有正 | Positive or negative正或负 | No monopole (N+S paired)无单极子(N、S 成对) |
| Force law力定律 | $F = \dfrac{G m_1 m_2}{r^2}$ | $F = \dfrac{k q_1 q_2}{r^2}$ | On moving charge only (D.3)仅作用于运动电荷(D.3) |
| Nature of force力的性质 | Always attractive恒为吸引 | Attract or repel可吸可斥 | Attract or repel (poles)可吸可斥(磁极) |
| Field lines场线 | Into mass; never cross指向质量;不相交 | Out of $+$, into $-$; never cross出 $+$、入 $-$;不相交 | Closed loops, N to S outside闭合回路,外部 N 到 S |
| Relative strength相对强度 | Extremely weak极弱 | Very strong很强 | Strong (depends on motion)强(取决于运动) |
Going deeper: why gravity dominates the cosmos despite being weakest深入:引力最弱却主宰宇宙的原因
Between two protons the electrostatic repulsion exceeds the gravitational attraction by a factor of about $10^{36}$. Yet gravity governs planets, stars and galaxies. The resolution is sign: electric charge comes in $+$ and $-$, so bulk matter is almost perfectly neutral and its electric forces cancel over large scales. Mass has only one sign, so gravitational pulls always add up — never cancel. Over astronomical distances the relentless accumulation of a tiny force wins.
两个质子之间的静电斥力约为引力吸引的 $10^{36}$ 倍。然而引力主宰行星、恒星与星系。原因在于符号:电荷有 $+$、$-$ 两种,故宏观物质几乎完全中性,其电力在大尺度上相互抵消。质量只有一种符号,引力吸引总是叠加——从不抵消。在天文距离上,微小力的持续累积最终取胜。
This same sign argument explains why electric field lines can terminate (on the opposite charge) while gravitational field lines, having no "negative mass" to end on, only ever point inward toward mass.
同样的符号论证解释了:电场线可以终止(在相反电荷上),而引力场线因没有"负质量"可终止,只能指向质量向内。
Exam Strategy and Common Pitfalls考试策略与常见陷阱
- Convert prefixes before substituting. $\mathrm{nC} \to 10^{-9}\ \mathrm{C}$, $\mu\mathrm{C} \to 10^{-6}\ \mathrm{C}$, $\mathrm{cm} \to 10^{-2}\ \mathrm{m}$. A missed factor of $10^{9}$ is the most common D.2 slip.
- 代入前先换算前缀。$\mathrm{nC} \to 10^{-9}\ \mathrm{C}$、$\mu\mathrm{C} \to 10^{-6}\ \mathrm{C}$、$\mathrm{cm} \to 10^{-2}\ \mathrm{m}$。漏掉 $10^{9}$ 是 D.2 最常见的错误。
- State magnitude and direction separately. Coulomb's law gives the size; you decide attract vs repel from the signs of the charges.
- 大小与方向分开陈述。库仑定律给出大小;由电荷符号判定吸引还是排斥。
- Don't confuse $E$ with $F$. $E = F/q$ is force per unit charge; it exists even where no test charge sits. Use $F = qE$ to get the actual force.
- 别混淆 $E$ 与 $F$。$E = F/q$ 是单位电荷受力;即使没有检验电荷它也存在。用 $F = qE$ 求实际力。
- Watch the power of $r$ HL. Field $E \propto 1/r^2$ but potential $V_e \propto 1/r$. Mixing these loses marks every year.
- 注意 $r$ 的幂次 HL。场 $E \propto 1/r^2$,电势 $V_e \propto 1/r$。混用每年都丢分。
- Add arrows. An unarrowed field-line sketch scores zero. Out of $+$, into $-$; N to S outside a magnet.
- 必须画箭头。无箭头的场线图得零分。出 $+$、入 $-$;磁铁外部 N 到 S。
- Keep parallel-plate lines straight, parallel and equally spaced. Bunching them implies a non-uniform field and loses the mark.
- 平行板场线要笔直、平行、等间距。画密了暗示非匀强场,会丢分。
- For "compare gravitational and electric fields", lead with the shared inverse-square form, then the sign difference (gravity attractive only).
- 遇到"比较引力场与电场",先讲共有的平方反比形式,再讲符号差异(引力只吸引)。
- For magnetic fields, the headline contrast is "closed loops, no monopole". Tie it to the field-line rules in your answer.
- 对磁场,核心对比是"闭合回路、无单极子"。答题时与场线规则联系起来。
Flashcards闪卡
Unit D.2 Practice Quiz单元 D.2 练习测验
Readiness Checklist备考清单
Tick each item when you can do it cold, without notes, on your first attempt.
每一条都要"裸做"做对(不看笔记、一次过)才打勾。
- Distinguish conductors from insulators and explain charging by friction/contact/induction区分导体与绝缘体,并解释摩擦/接触/感应起电
- Apply Coulomb's law $F = k q_1 q_2 / r^2$ with correct prefix conversions and state attract vs repel用库仑定律 $F = k q_1 q_2 / r^2$ 并正确换算前缀,说明吸引或排斥
- Use $E = F/q$ and the radial field $E = kQ/r^2$, distinguishing field from force使用 $E = F/q$ 与径向场 $E = kQ/r^2$,区分场与力
- Sketch field lines for a point charge and for a dipole, with arrows and correct density为点电荷与偶极子画带箭头、密度正确的电场线
- Compute the uniform field $E = V/d$ between plates and the force $F = qE$ on a charge计算平行板间匀强场 $E = V/d$ 与电荷受力 $F = qE$
- Explain why $\mathrm{N\,C^{-1}}$ and $\mathrm{V\,m^{-1}}$ are the same unit解释为何 $\mathrm{N\,C^{-1}}$ 与 $\mathrm{V\,m^{-1}}$ 是同一单位
- Draw and interpret the magnetic field of a bar magnet (N to S, densest at poles)画出并解读条形磁铁的磁场(N 到 S,两极最密)
- Apply the right-hand grip rule to find $B$ around a straight wire and inside a solenoid用右手螺旋定则求直导线周围与螺线管内部的 $B$
- State that magnetic field lines form closed loops because there are no monopoles说明磁感线构成闭合回路是因为不存在磁单极子
- Compare gravitational, electric and magnetic fields by source, sign and field-line rules从源、符号与场线规则对比引力场、电场与磁场
- HL Use $V_e = kQ/r$ and $E_p = k q_1 q_2 / r$, and compute work via $W = q\,\Delta V_e$使用 $V_e = kQ/r$ 与 $E_p = k q_1 q_2 / r$,并用 $W = q\,\Delta V_e$ 求功
- HL Relate equipotentials to field lines and recall $V_e \propto 1/r$ while $E \propto 1/r^2$把等势面与电场线联系,并记住 $V_e \propto 1/r$ 而 $E \propto 1/r^2$
IB Paper-Style PracticeIB 试卷风格练习
D.2 Practice and Solutions are on the roadmap, to ship under Practice Questions/Unit_D2_*.html with the bilingual built-in pattern.
D.2 配套 Practice 与 Solutions 在排期,上线后位于 Practice Questions/Unit_D2_*.html。