IB Physics HL · 鼎睿学苑

Unit D.2: Electric and Magnetic Fields单元 D.2:电场与磁场

Part of Theme D "Fields". Electric charge, conductors and insulators, Coulomb's law, electric field strength and field-line patterns, the uniform field between parallel plates, and the magnetic-field patterns of bar magnets, current-carrying wires and solenoids. The HL extension introduces electric potential and electric potential energy, equipotentials, and the field-potential link. The unit closes by comparing gravitational, electric and magnetic fields in one synthesis table. This material is the foundation for D.3 (motion in EM fields) and D.4 (induction).主题 D"场"的一部分。电荷、导体与绝缘体、库仑定律、电场强度与电场线图样、平行板间的匀强电场,以及条形磁铁、载流导线与螺线管的磁场图样。HL 扩展引入电势、电势能、等势面以及场-势之间的关系。本单元以一张综合表对比引力场、电场与磁场作结。这些内容是 D.3(电磁场中的运动)与 D.4(电磁感应)的基础。

IB Physics · Theme D.2 · First Assessment 2025 Papers 1 · 2 6 Topics · SL + HL mix6 个核心专题 · SL + HL 混合

How to use this guide本指南使用说明

D.2 is built on one idea repeated three ways: a source creates a field, and the field exerts a force on whatever you place in it. Master the parallel structure — Coulomb force vs field strength, point-charge field vs uniform field, electric vs magnetic — and most marks fall out of substitution. The arithmetic uses powers of ten ($k = 8.99 \times 10^{9}$, charges in $\mathrm{nC}$ or $\mu\mathrm{C}$), so train your calculator discipline alongside the physics.D.2 的核心是同一思想的三种表述:源产生场,场对放入其中的物体施力。掌握这种平行结构——库仑力与电场强度、点电荷场与匀强场、电场与磁场——大多数分数都来自代入计算。运算涉及 10 的幂次($k = 8.99 \times 10^{9}$,电荷常以 $\mathrm{nC}$ 或 $\mu\mathrm{C}$ 计),因此物理与计算器规范要一起练。

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If you are cramming如果你在临阵磨枪

Memorise three force/field equations: Coulomb's law $F = \dfrac{k q_1 q_2}{r^2}$, field of a point charge $E = \dfrac{kQ}{r^2}$, and the uniform-plate field $E = \dfrac{V}{d}$ with $F = qE$. Field lines: out of positive, into negative, never crossing. Magnetic field: north to south outside a magnet; right-hand grip rule for a wire.

背熟三条力/场公式:库仑定律 $F = \dfrac{k q_1 q_2}{r^2}$、点电荷场 $E = \dfrac{kQ}{r^2}$、平行板匀强场 $E = \dfrac{V}{d}$ 且 $F = qE$。电场线:出正入负、永不相交。磁场:磁铁外部由北指向南;导线用右手螺旋定则。

If you are going for a 7如果你目标是 7 分

Be fluent moving between field and potential HL: $V_e = \dfrac{kQ}{r}$, $E_p = \dfrac{k q_1 q_2}{r}$, equipotentials perpendicular to field lines, and $W = q \Delta V_e$. Know why the electric force can be attractive or repulsive while gravity is only attractive, and why magnetic field lines form closed loops with no monopole source. Sketch dipole and solenoid patterns from memory.

能在场与势之间自如转换 HL:$V_e = \dfrac{kQ}{r}$、$E_p = \dfrac{k q_1 q_2}{r}$、等势面垂直于电场线、$W = q \Delta V_e$。理解为何电力可吸可斥而引力只能吸引,以及磁感线为何是无磁单极源的闭合回路。能默画偶极子与螺线管的场图样。

HL flagHL 标记说明 Section D2.4 (electric potential $V_e$ and electric potential energy $E_p$, equipotentials, and the field–potential link) is HL extension content. SL students may safely skip the HL-flagged blocks; everything else in this unit is common SL + HL.D2.4(电势 $V_e$ 与电势能 $E_p$、等势面以及场-势关系)为 HL 扩展内容。SL 学生可跳过带 HL 标记的段落;本单元其余内容为 SL + HL 共同要求。

Electric Charge, Conductors & Insulators, Coulomb's Law电荷、导体与绝缘体、库仑定律 D.2 SL+HL

Charge basics.
  • Charge $q$ is quantised in units of $e = 1.60 \times 10^{-19}\ \mathrm{C}$; like charges repel, unlike attract.
  • Conductor: free charge carriers (electrons in metals) move easily. Insulator: charges are bound and do not flow.
  • Charge is conserved: it is transferred (friction, contact, induction), never created or destroyed.
Coulomb's law (data booklet). Use F = kq₁q₂ / r²: $$ F = \frac{k q_1 q_2}{r^2}, \qquad k = \frac{1}{4\pi\varepsilon_0} = 8.99 \times 10^{9}\ \mathrm{N\,m^2\,C^{-2}}. $$ Sign rule. A positive product $q_1 q_2 > 0$ means repulsion; negative means attraction. Always state the direction separately from the magnitude.
电荷基础。
  • 电荷(charge)$q$ 以 $e = 1.60 \times 10^{-19}\ \mathrm{C}$ 为单位量子化;同号相斥、异号相吸。
  • 导体(conductor):自由载流子(金属中的电子)易于移动。绝缘体(insulator):电荷被束缚,不能流动。
  • 电荷守恒:只能转移(摩擦、接触、感应),不能凭空产生或消失。
库仑定律(数据手册)。F = kq₁q₂ / r²: $$ F = \frac{k q_1 q_2}{r^2}, \qquad k = \frac{1}{4\pi\varepsilon_0} = 8.99 \times 10^{9}\ \mathrm{N\,m^2\,C^{-2}}. $$ 符号规则。乘积 $q_1 q_2 > 0$ 表示相斥;为负表示相吸。方向要与大小分开说明。

Worked Example D2.1 (force between two point charges)D2.1 例题(两点电荷间的作用力)

Two point charges $q_1 = +3.0\ \mathrm{nC}$ and $q_2 = -5.0\ \mathrm{nC}$ are separated by $4.0\ \mathrm{cm}$ in vacuum. Find the magnitude and nature of the electrostatic force between them.真空中两点电荷 $q_1 = +3.0\ \mathrm{nC}$ 与 $q_2 = -5.0\ \mathrm{nC}$ 相距 $4.0\ \mathrm{cm}$。求它们之间静电力的大小与性质。

Identify. Coulomb's law with $k = 8.99 \times 10^{9}$, $r = 0.040\ \mathrm{m}$. Convert charges: $3.0\ \mathrm{nC} = 3.0 \times 10^{-9}\ \mathrm{C}$, $5.0\ \mathrm{nC} = 5.0 \times 10^{-9}\ \mathrm{C}$.

识别。用库仑定律,$k = 8.99 \times 10^{9}$、$r = 0.040\ \mathrm{m}$。换算电荷:$3.0\ \mathrm{nC} = 3.0 \times 10^{-9}\ \mathrm{C}$、$5.0\ \mathrm{nC} = 5.0 \times 10^{-9}\ \mathrm{C}$。

Substitute (use magnitudes for the size):

代入(用电荷大小求力的大小):

$$ F = \frac{(8.99 \times 10^{9})(3.0 \times 10^{-9})(5.0 \times 10^{-9})}{(0.040)^2}. $$ $$ F = \frac{8.99 \times 10^{9} \times 1.5 \times 10^{-17}}{1.6 \times 10^{-3}} \approx 8.4 \times 10^{-5}\ \mathrm{N}. $$

Evaluate. Magnitude $\approx 8.4 \times 10^{-5}\ \mathrm{N}$. Since the charges are unlike, the force is attractive — each charge is pulled toward the other along the line joining them.

评估。大小约 $8.4 \times 10^{-5}\ \mathrm{N}$。两电荷异号,故为吸引力——沿连线相互拉近。

Going deeper: the inverse-square law and superposition深入:平方反比与叠加原理

Coulomb's law is an inverse-square law: doubling $r$ quarters the force. This shares its mathematical form with Newton's law of gravitation $F = \dfrac{G m_1 m_2}{r^2}$ — a parallel we exploit in D2.6.

库仑定律是平方反比律:$r$ 加倍,力变为四分之一。它与牛顿万有引力 $F = \dfrac{G m_1 m_2}{r^2}$ 形式相同——这一平行关系将在 D2.6 中利用。

For more than two charges, the net force on any one charge is the vector sum of the individual Coulomb forces (superposition). Resolve each pairwise force into components, add component-wise, then recombine. The constant can be written either as $k$ or via the permittivity of free space $\varepsilon_0 = 8.85 \times 10^{-12}\ \mathrm{C^2\,N^{-1}\,m^{-2}}$, since $k = \dfrac{1}{4\pi\varepsilon_0}$.

超过两个电荷时,某电荷所受合力是各对库仑力的矢量和(叠加原理)。把每对力分解为分量、按分量相加、再合成。常数可写为 $k$,也可用真空介电常数 $\varepsilon_0 = 8.85 \times 10^{-12}\ \mathrm{C^2\,N^{-1}\,m^{-2}}$,因为 $k = \dfrac{1}{4\pi\varepsilon_0}$。

Two point charges experience a force $F$ at separation $r$. If the separation is tripled to $3r$ with charges unchanged, the new force is:两点电荷在间距 $r$ 时受力 $F$。若间距增至 $3r$、电荷不变,则新力为:
D2.1 · Q1
$F/3$
$F/9$
$3F$
$9F$
Coulomb's law is inverse-square: $F \propto 1/r^2$. Tripling $r$ multiplies $r^2$ by $9$, so the force becomes $F/9$.库仑定律为平方反比:$F \propto 1/r^2$。$r$ 变 3 倍则 $r^2$ 变 9 倍,故力变为 $F/9$。
Force depends on $1/r^2$, not $1/r$. Cube of changes in $r$ are not relevant; square the factor by which $r$ changes.力依赖 $1/r^2$,不是 $1/r$。要对 $r$ 的变化倍数取平方。
A glass rod rubbed with silk becomes positively charged. This happened because:玻璃棒用丝绸摩擦后带正电。这是因为:
D2.1 · Q2
Protons moved from the silk to the rod质子从丝绸转移到玻璃棒
New positive charge was created on the rod玻璃棒上产生了新的正电荷
Electrons were transferred from the rod to the silk电子从玻璃棒转移到丝绸
The rod gained electrons from the silk玻璃棒从丝绸获得了电子
Charging by friction transfers electrons, not protons. The rod loses electrons to the silk, leaving it with a net positive charge. Charge is conserved overall.摩擦起电转移的是电子而非质子。玻璃棒把电子转移给丝绸,自身带净正电。整体电荷守恒。
Only electrons move in solids; protons are locked in nuclei. Charge is never created — a positive object has lost electrons.固体中只有电子移动,质子被锁在原子核内。电荷不会被创造——带正电意味着失去了电子。

Electric Field Strength and Field-Line Patterns电场强度与电场线图样 D.2 SL+HL

Field strength definition. Force per unit positive test charge. From the data booklet, E = F / q: $$ E = \frac{F}{q}, \qquad E = \frac{kQ}{r^2}\ \text{(radial, point charge $Q$)}. $$ Units $\mathrm{N\,C^{-1}}$ (equivalently $\mathrm{V\,m^{-1}}$). $E$ is a vector pointing in the direction of the force on a positive charge. Field-line rules.
  • Lines point out of positive charges, into negative charges.
  • Density of lines $\propto$ field strength; lines never cross.
  • Point charge: radial lines. Dipole ($+$ and $-$): lines curve from $+$ to $-$.
电场强度定义。单位正检验电荷所受的力。数据手册中 E = F / q: $$ E = \frac{F}{q}, \qquad E = \frac{kQ}{r^2}\ \text{(点电荷 $Q$ 的径向场)}. $$ 单位 $\mathrm{N\,C^{-1}}$(等价于 $\mathrm{V\,m^{-1}}$)。$E$ 是矢量,指向电荷所受力的方向。 电场线规则。
  • 电场线从正电荷发出,在负电荷终止
  • 线的疏密 $\propto$ 场强;电场线永不相交。
  • 点电荷:径向线。偶极子($+$ 与 $-$):线从 $+$ 弯向 $-$。
Worked Example D2.2 (radial field of a point charge)D2.2 例题(点电荷的径向场)

A point charge $Q = +6.0\ \mathrm{nC}$ sits in vacuum. (a) Find the electric field strength at $r = 0.20\ \mathrm{m}$. (b) Find the force on a test charge $q = -2.0\ \mathrm{nC}$ placed there.真空中有点电荷 $Q = +6.0\ \mathrm{nC}$。(a) 求 $r = 0.20\ \mathrm{m}$ 处的电场强度。(b) 求放在该处的检验电荷 $q = -2.0\ \mathrm{nC}$ 所受的力。

(a) Field strength. Radial point-charge field $E = \dfrac{kQ}{r^2}$:

(a) 场强。点电荷径向场 $E = \dfrac{kQ}{r^2}$:

$$ E = \frac{(8.99 \times 10^{9})(6.0 \times 10^{-9})}{(0.20)^2} = \frac{53.9}{0.040} \approx 1.35 \times 10^{3}\ \mathrm{N\,C^{-1}}. $$

Direction: radially outward (away from the positive source).

方向:沿径向向外(背离正源)。

(b) Force on the test charge. Use $F = qE$ with magnitudes:

(b) 检验电荷受力。用 $F = qE$(取大小):

$$ F = qE = (2.0 \times 10^{-9})(1.35 \times 10^{3}) \approx 2.7 \times 10^{-6}\ \mathrm{N}. $$

Evaluate. The test charge is negative, so the force is opposite to $E$ — directed radially inward, toward $Q$ (attraction). Magnitude $\approx 2.7\ \mu\mathrm{N}$.

评估。检验电荷为负,受力与 $E$ 相反——沿径向向内,指向 $Q$(吸引)。大小约 $2.7\ \mu\mathrm{N}$。

Going deeper: why field lines never cross, and reading dipole patterns深入:电场线为何不相交,以及读偶极子图样

At every point the field has a single, definite direction (the net force per unit charge there). If two field lines crossed, the field would have two directions at the crossing point — a contradiction. Hence lines never intersect.

每一点的场都有唯一确定的方向(该处单位电荷受到的合力)。若两条电场线相交,交点处的场将有两个方向——矛盾。因此电场线不相交。

For a dipole (equal $+$ and $-$ charges), lines leave the positive charge, curve through space, and enter the negative charge. Exactly midway on the perpendicular bisector the field is non-zero and points from $+$ toward $-$. Contrast with two like charges: there a null point (zero field) sits midway, and lines push apart rather than join.

对偶极子(等量 $+$ 与 $-$),电场线从正电荷发出、在空间弯曲、终止于负电荷。在中垂线正中点处场不为零,由 $+$ 指向 $-$。与两个同号电荷对比:那里中点是零场点,电场线互相排开而非相连。

The electric field strength at a point due to a point charge is $E$. At a point twice as far away, the field strength is:某点处由点电荷产生的电场强度为 $E$。在距离加倍处,场强为:
D2.2 · Q1
$2E$
$E/2$
$E/4$
$E$
$E = kQ/r^2 \propto 1/r^2$. Doubling $r$ divides the field by $2^2 = 4$, giving $E/4$.$E = kQ/r^2 \propto 1/r^2$。$r$ 加倍则场强除以 $2^2 = 4$,得 $E/4$。
Field strength of a point charge follows the inverse-square law, like the force. Square the distance factor.点电荷场强遵循平方反比律(与力相同)。要对距离倍数取平方。
Which statement about electric field lines is correct?关于电场线,下列哪项正确?
D2.2 · Q2
They point from negative charges to positive charges由负电荷指向正电荷
They can cross where two fields overlap在两场叠加处可以相交
They are closer together where the field is weaker在场较弱处更密集
They show the direction of force on a positive test charge表示正检验电荷所受力的方向
By convention a field line shows the direction a positive test charge would be pushed. Lines run out of $+$ into $-$, never cross, and crowd together where the field is stronger.按约定,电场线表示正检验电荷被推动的方向。线由 $+$ 出、入 $-$,永不相交,并在场较强处更密集。
Lines run from $+$ to $-$, never cross, and are denser where the field is stronger. Only the force-direction statement is correct.电场线由 $+$ 到 $-$,不相交,场强处更密。只有"力的方向"那项正确。

Uniform Electric Field Between Parallel Plates平行板间的匀强电场 D.2 SL+HL

Uniform field. Between two parallel plates a distance $d$ apart held at potential difference $V$, the field is uniform (constant magnitude and direction). From the data booklet, E = V / d: $$ E = \frac{V}{d}, \qquad F = qE = \frac{qV}{d}. $$ Key features.
  • Field lines are straight, parallel, equally spaced, from the $+$ plate to the $-$ plate.
  • The force on a charge is the same everywhere between the plates — analogous to gravity near Earth's surface.
  • Edge effects (fringing) are ignored at the IB level.
匀强电场。相距 $d$、电势差为 $V$ 的两平行板之间,场是匀强的(大小、方向恒定)。数据手册中 E = V / d: $$ E = \frac{V}{d}, \qquad F = qE = \frac{qV}{d}. $$ 关键特征。
  • 电场线笔直、平行、等间距,从 $+$ 板指向 $-$ 板。
  • 板间各处对电荷的力处处相同——类比地表附近的重力。
  • IB 层面忽略边缘效应(边缘发散)。
Worked Example D2.3 (charge between charged plates)D2.3 例题(带电板间的电荷)

Two horizontal parallel plates are separated by $d = 2.0\ \mathrm{cm}$ and connected to a $V = 300\ \mathrm{V}$ supply. (a) Find the field strength between them. (b) Find the force on an oil droplet carrying charge $q = 3.2 \times 10^{-19}\ \mathrm{C}$ (two electron charges).两水平平行板相距 $d = 2.0\ \mathrm{cm}$,接 $V = 300\ \mathrm{V}$ 电源。(a) 求板间场强。(b) 求带电 $q = 3.2 \times 10^{-19}\ \mathrm{C}$(两个电子电荷)的油滴所受的力。

(a) Field strength. $E = \dfrac{V}{d}$ with $d = 0.020\ \mathrm{m}$:

(a) 场强。$E = \dfrac{V}{d}$,$d = 0.020\ \mathrm{m}$:

$$ E = \frac{300}{0.020} = 1.5 \times 10^{4}\ \mathrm{V\,m^{-1}}. $$

(b) Force. $F = qE$:

(b) 受力。$F = qE$:

$$ F = (3.2 \times 10^{-19})(1.5 \times 10^{4}) \approx 4.8 \times 10^{-15}\ \mathrm{N}. $$

Evaluate. The force has the same value anywhere between the plates because the field is uniform. This is the principle behind Millikan's oil-drop experiment, where this electric force is balanced against the droplet's weight.

评估。因场为匀强,板间各处受力相同。这正是密立根油滴实验的原理:用此电力平衡油滴重力。

Going deeper: why $\mathrm{N\,C^{-1}}$ and $\mathrm{V\,m^{-1}}$ are the same unit深入:为何 $\mathrm{N\,C^{-1}}$ 与 $\mathrm{V\,m^{-1}}$是同一单位

From $E = V/d$, the field has units $\mathrm{V\,m^{-1}}$. From $E = F/q$, it has units $\mathrm{N\,C^{-1}}$. These are identical because $1\ \mathrm{V} = 1\ \mathrm{J\,C^{-1}}$ and $1\ \mathrm{J} = 1\ \mathrm{N\,m}$:

由 $E = V/d$,场的单位为 $\mathrm{V\,m^{-1}}$。由 $E = F/q$,单位为 $\mathrm{N\,C^{-1}}$。二者相同,因为 $1\ \mathrm{V} = 1\ \mathrm{J\,C^{-1}}$ 且 $1\ \mathrm{J} = 1\ \mathrm{N\,m}$:

$$ \frac{\mathrm{V}}{\mathrm{m}} = \frac{\mathrm{J\,C^{-1}}}{\mathrm{m}} = \frac{\mathrm{N\,m\,C^{-1}}}{\mathrm{m}} = \mathrm{N\,C^{-1}}. $$

A charged particle entering a uniform field perpendicular to the field lines follows a parabolic path, exactly like a projectile in gravity: constant velocity along the plates, constant acceleration $a = qE/m$ across them. That trajectory analysis is developed in D.3.

带电粒子垂直于电场线进入匀强场后走抛物线,与重力中的抛体完全类似:沿板方向匀速,垂直方向匀加速 $a = qE/m$。该轨迹分析在 D.3 展开。

The potential difference across two parallel plates is doubled while their separation is halved. The field strength between them:两平行板间电势差加倍、间距减半。板间场强:
D2.3 · Q1
Increases by a factor of 4增大为原来的 4 倍
Doubles加倍
Stays the same不变
Halves减半
$E = V/d$. Doubling $V$ doubles $E$; halving $d$ doubles $E$ again. Net factor $2 \times 2 = 4$.$E = V/d$。$V$ 加倍使 $E$ 加倍;$d$ 减半再使 $E$ 加倍。总倍数 $2 \times 2 = 4$。
$E = V/d$. $V$ in the numerator and $d$ in the denominator both push $E$ up here: factor $2 \times 2 = 4$.$E = V/d$。分子 $V$ 与分母 $d$ 在此都使 $E$ 增大:倍数 $2 \times 2 = 4$。
A charge $+q$ is moved from a point near the positive plate to a point near the negative plate of a parallel-plate capacitor. The electric force on it during the trip:电荷 $+q$ 在平行板电容器中从靠近正板移到靠近负板。途中所受电力:
D2.3 · Q2
Increases as it approaches the negative plate越靠近负板越大
Decreases as it approaches the negative plate越靠近负板越小
Stays constant throughout全程保持不变
Reverses direction halfway中途方向反转
The field between parallel plates is uniform, so $F = qE$ has the same magnitude and direction everywhere. The force is constant, like weight near Earth's surface.平行板间为匀强场,故 $F = qE$ 处处大小方向相同。受力恒定,如地表附近的重力。
Unlike a point-charge field, the parallel-plate field does not vary with position — it is uniform, so the force is constant.与点电荷场不同,平行板场不随位置变化——它是匀强场,故力恒定。

Electric Potential and Electric Potential Energy电势与电势能 HL D.2 HL

HL only仅 HL This entire section (D2.4) is HL extension material. SL students are not assessed on electric potential or electric potential energy and may skip to D2.5.本节(D2.4)全部为 HL 扩展内容。SL 学生不考电势与电势能,可直接跳到 D2.5。
Electric potential (HL). The work done per unit charge to bring a small positive test charge from infinity to a point. From the data booklet, Vₑ = kQ / r: $$ V_e = \frac{kQ}{r} \quad (\mathrm{V} = \mathrm{J\,C^{-1}}). $$ Electric potential energy (HL). Of a pair of point charges, from the data booklet Eₚ = kq₁q₂ / r: $$ E_p = \frac{k q_1 q_2}{r} = q V_e. $$ Work done (HL). Moving charge $q$ between two points: $W = q\,\Delta V_e$. Equipotentials. Surfaces of constant $V_e$; always perpendicular to field lines. No work is done moving a charge along an equipotential.
电势(HL)。把单位小正检验电荷从无穷远移到某点所做的功。数据手册中 Vₑ = kQ / r: $$ V_e = \frac{kQ}{r} \quad (\mathrm{V} = \mathrm{J\,C^{-1}}). $$ 电势能(HL)。一对点电荷的电势能,数据手册中 Eₚ = kq₁q₂ / r: $$ E_p = \frac{k q_1 q_2}{r} = q V_e. $$ 所做的功(HL)。把电荷 $q$ 在两点间移动:$W = q\,\Delta V_e$。 等势面。$V_e$ 恒定的面;总与电场线垂直。沿等势面移动电荷不做功。
Worked Example D2.4 (potential and work) HLD2.4 例题(电势与功) HL

A point charge $Q = +4.0\ \mathrm{nC}$ is in vacuum. (a) Find the electric potential at $r_1 = 0.10\ \mathrm{m}$ and at $r_2 = 0.30\ \mathrm{m}$. (b) Find the work done by an external agent moving a charge $q = +2.0\ \mathrm{nC}$ from $r_2$ to $r_1$.真空中点电荷 $Q = +4.0\ \mathrm{nC}$。(a) 求 $r_1 = 0.10\ \mathrm{m}$ 与 $r_2 = 0.30\ \mathrm{m}$ 处的电势。(b) 求外力把电荷 $q = +2.0\ \mathrm{nC}$ 从 $r_2$ 移到 $r_1$ 所做的功。

(a) Potentials. $V_e = \dfrac{kQ}{r}$:

(a) 各处电势。$V_e = \dfrac{kQ}{r}$:

$$ V_1 = \frac{(8.99 \times 10^{9})(4.0 \times 10^{-9})}{0.10} \approx 360\ \mathrm{V}, $$ $$ V_2 = \frac{(8.99 \times 10^{9})(4.0 \times 10^{-9})}{0.30} \approx 120\ \mathrm{V}. $$

(b) Work done. $W = q\,\Delta V_e = q (V_1 - V_2)$:

(b) 所做的功。$W = q\,\Delta V_e = q (V_1 - V_2)$:

$$ W = (2.0 \times 10^{-9})(360 - 120) = (2.0 \times 10^{-9})(240) \approx 4.8 \times 10^{-7}\ \mathrm{J}. $$

Evaluate. Positive work is required: moving a positive charge toward a positive source raises its potential energy (pushing against repulsion). The agent does $\approx 0.48\ \mu\mathrm{J}$ on the charge.

评估。需做正功:把正电荷推向正源会升高其电势能(逆着斥力)。外力对电荷做功约 $0.48\ \mu\mathrm{J}$。

Going deeper: the field–potential link HL深入:场-势关系 HL

Electric field strength is the negative gradient of potential: the field points "downhill" in potential, from high $V_e$ to low $V_e$. For a uniform field this reduces to the relation you already met:

电场强度是电势的负梯度:场指向电势"下坡"方向,由高 $V_e$ 指向低 $V_e$。对匀强场,这退化为你已学过的关系:

$$ E = -\frac{\Delta V_e}{\Delta r}, \qquad \text{(uniform field)}\ E = \frac{V}{d}. $$

On a diagram, equipotentials are like contour lines on a map and field lines are the steepest-descent paths crossing them at right angles. Closely spaced equipotentials mean a large $\Delta V_e$ over a small $\Delta r$, hence a strong field. Note the sign and distance contrast with PE: potential $V_e \propto 1/r$ falls off more slowly than field $E \propto 1/r^2$.

在图上,等势面如地图上的等高线,电场线则是与之处处垂直的最陡下降路径。等势面越密表示小 $\Delta r$ 上有大 $\Delta V_e$,即场越强。注意与场的距离差别:电势 $V_e \propto 1/r$ 比场 $E \propto 1/r^2$ 衰减更慢。

HL The electric potential a distance $r$ from a point charge is $V_e$. At a distance $2r$ the potential is:HL 距点电荷 $r$ 处的电势为 $V_e$。在 $2r$ 处电势为:
D2.4 · Q1
$V_e / 4$
$V_e / 2$
$2 V_e$
$V_e$
$V_e = kQ/r \propto 1/r$ (not $1/r^2$). Doubling $r$ halves the potential, giving $V_e/2$. Potential falls off more slowly than field.$V_e = kQ/r \propto 1/r$(不是 $1/r^2$)。$r$ 加倍使电势减半,得 $V_e/2$。电势比场衰减更慢。
Careful: potential goes as $1/r$, while field strength goes as $1/r^2$. Doubling $r$ halves $V_e$.注意:电势按 $1/r$ 变化,而场强按 $1/r^2$。$r$ 加倍使 $V_e$ 减半。
HL A charge is moved along an equipotential surface. The work done on it is:HL 把电荷沿等势面移动。对它所做的功为:
D2.4 · Q2
Equal to $q V_e$等于 $q V_e$
Maximum, since the field is strongest there最大,因为该处场最强
Zero, because the potential does not change为零,因为电势不变
Negative, because the charge loses energy为负,因为电荷损失能量
$W = q\,\Delta V_e$. Along an equipotential $\Delta V_e = 0$, so $W = 0$. The motion is everywhere perpendicular to the field, so the field does no work.$W = q\,\Delta V_e$。沿等势面 $\Delta V_e = 0$,故 $W = 0$。运动处处垂直于场,场不做功。
Work depends on the change in potential, $W = q\,\Delta V_e$. On an equipotential $\Delta V_e = 0$, so no work is done.功取决于电势变化 $W = q\,\Delta V_e$。等势面上 $\Delta V_e = 0$,故不做功。

Magnetic Fields: Magnets, Wires and Solenoids磁场:磁铁、导线与螺线管 D.2 SL+HL

Magnetic field $B$. A vector field around magnets and moving charges. Field lines (magnetic flux lines) point from north to south outside the magnet and form closed loops (there are no magnetic monopoles). Three patterns to know.
  • Bar magnet: lines emerge from N, curve round, enter S; densest (strongest) at the poles.
  • Long straight wire: concentric circles around the wire. Right-hand grip rule: thumb along the conventional current, fingers curl in the direction of $B$.
  • Solenoid: uniform field inside (like a bar magnet's exterior), with N and S ends set by the grip rule applied to the coils.
磁场 $B$。磁铁与运动电荷周围的矢量场。磁感线(磁通量线)在磁铁外部由北指向南,并构成闭合回路(不存在磁单极子)。 三种须掌握的图样。
  • 条形磁铁:磁感线由 N 出、绕行、入 S;两极处最密(最强)。
  • 长直导线:环绕导线的同心圆。右手螺旋定则:拇指沿常规电流方向,四指弯曲方向即 $B$ 的方向。
  • 螺线管(solenoid):内部匀强场(如条形磁铁外部),N、S 端由对线圈用螺旋定则确定。
Worked Example D2.5 (field direction around a wire)D2.5 例题(导线周围的场方向)

A long straight vertical wire carries conventional current upward (out of the floor toward the ceiling). Determine the direction of the magnetic field at a point due north of the wire, and at a point due east of it.一根长直竖直导线中常规电流向上(由地面指向天花板)。判断导线正北方某点与正东方某点处磁场的方向。

Identify. Use the right-hand grip rule: point the thumb upward (current direction); the fingers curl anticlockwise when viewed from above.

识别。用右手螺旋定则:拇指向上(电流方向);从上方看,四指逆时针弯曲。

North point. At a point north of the wire, the anticlockwise circulation (viewed from above) points the field toward the west.

正北点。在导线正北处,(俯视)逆时针环流使该点场指向正西

East point. Continuing anticlockwise, at a point east of the wire the field points toward the north.

正东点。沿逆时针继续,在导线正东处场指向正北

Evaluate. The field circulates in horizontal circles around the vertical wire, anticlockwise seen from above. Its magnitude falls with distance from the wire, so the circles are most tightly "felt" close in.

评估。场在竖直导线周围作水平圆周环流,俯视为逆时针。其大小随离导线距离增大而减小,故近处场最强。

Going deeper: why magnetic field lines are closed loops深入:磁感线为何是闭合回路

Electric field lines start and end on charges (sources and sinks). Magnetic field lines never start or stop — they always form complete closed loops. The deep reason is that no isolated magnetic "charge" (a monopole) has ever been found: cut a bar magnet in half and you get two smaller magnets, each with its own N and S.

电场线起止于电荷(源与汇)。磁感线既不起也不止——总是构成完整闭合回路。根本原因是从未发现孤立的磁"荷"(磁单极子):把条形磁铁切成两半会得到两块更小的磁铁,各自仍有 N、S 极。

Inside a solenoid, the loops from all the turns reinforce to give a nearly uniform interior field; outside, the return paths spread out and weaken, giving the solenoid the same external pattern as a bar magnet. This equivalence is why a current-carrying coil is an electromagnet, and reversing the current swaps its N and S ends.

在螺线管内部,各匝的回路相互增强,形成近乎匀强的内部场;外部,回路返回路径展开变弱,使螺线管外部图样与条形磁铁相同。正因这种等价,载流线圈即为电磁铁,反转电流即可互换其 N、S 端。

A long straight wire carries current into the page. The magnetic field lines around it are:一根长直导线中电流方向指入纸面。其周围的磁感线为:
D2.5 · Q1
Straight lines radiating outward from the wire从导线向外辐射的直线
Concentric circles, anticlockwise同心圆,逆时针
Concentric circles, clockwise同心圆,顺时针
Straight lines parallel to the wire与导线平行的直线
Right-hand grip rule: thumb into the page (current direction), fingers curl clockwise as seen from the front. The lines are concentric circles around the wire, directed clockwise.右手螺旋定则:拇指指入纸面(电流方向),从正面看四指顺时针弯曲。磁感线是绕导线的同心圆,方向顺时针。
A wire's field circulates in concentric circles (not radial or parallel lines). Grip rule with current into the page gives clockwise circulation.导线的场是同心圆环流(非辐射或平行直线)。电流入纸面时螺旋定则给出顺时针。
Which is the key difference between magnetic and electric field lines?磁感线与电场线的关键区别是?
D2.5 · Q2
Magnetic lines can cross; electric lines cannot磁感线可相交,电场线不可
Electric lines form closed loops; magnetic lines do not电场线构成闭合回路,磁感线不构成
Magnetic lines show force on a stationary charge磁感线表示静止电荷所受的力
Magnetic lines form closed loops; electric lines start and end on charges磁感线构成闭合回路,电场线起止于电荷
Magnetic field lines are always closed loops (no monopoles), whereas electric field lines begin on positive charges and end on negative charges. Neither set of lines ever crosses.磁感线永远是闭合回路(无磁单极子),而电场线起于正电荷、止于负电荷。两类线都不相交。
Neither type crosses. Magnetic lines are the closed loops (no monopole); electric lines start/end on charges. A stationary charge feels no magnetic force.两类线都不相交。磁感线是闭合回路(无单极子);电场线起止于电荷。静止电荷不受磁力。

Comparing Gravitational, Electric and Magnetic Fields引力场、电场与磁场的对比 D.2 SL+HL

Same skeleton, different sources. All three are vector fields where a source creates a field and the field exerts a force. The gravitational and electric force laws share the inverse-square form; the deepest split is sign: gravity is always attractive, electric forces can attract or repel, and magnetic forces act only on moving charges. Key parallels.
  • Force: $F = \dfrac{G m_1 m_2}{r^2}$ vs $F = \dfrac{k q_1 q_2}{r^2}$.
  • Field: $g = \dfrac{GM}{r^2}$ vs $E = \dfrac{kQ}{r^2}$.
  • "Charge" of the field: mass $m$ (only positive) vs charge $q$ ($\pm$) vs there is no magnetic monopole.
同一骨架,不同的源。三者都是矢量场:源产生场,场施力。引力与电力的力定律共享平方反比形式;最根本的区别是符号:引力恒为吸引,电力可吸可斥,而磁力只作用于运动电荷。 关键平行关系。
  • 力:$F = \dfrac{G m_1 m_2}{r^2}$ 与 $F = \dfrac{k q_1 q_2}{r^2}$。
  • 场:$g = \dfrac{GM}{r^2}$ 与 $E = \dfrac{kQ}{r^2}$。
  • 场的"荷":质量 $m$(只为正)与电荷 $q$($\pm$)与不存在磁单极子。
Feature特征 Gravitational引力场 Electric电场 Magnetic磁场
Source Mass $m$质量 $m$ Charge $q$电荷 $q$ Moving charge / magnet运动电荷 / 磁铁
Sign of "charge""荷"的符号 Positive only只有正 Positive or negative正或负 No monopole (N+S paired)无单极子(N、S 成对)
Force law力定律 $F = \dfrac{G m_1 m_2}{r^2}$ $F = \dfrac{k q_1 q_2}{r^2}$ On moving charge only (D.3)仅作用于运动电荷(D.3)
Nature of force力的性质 Always attractive恒为吸引 Attract or repel可吸可斥 Attract or repel (poles)可吸可斥(磁极)
Field lines场线 Into mass; never cross指向质量;不相交 Out of $+$, into $-$; never cross出 $+$、入 $-$;不相交 Closed loops, N to S outside闭合回路,外部 N 到 S
Relative strength相对强度 Extremely weak极弱 Very strong很强 Strong (depends on motion)强(取决于运动)
Going deeper: why gravity dominates the cosmos despite being weakest深入:引力最弱却主宰宇宙的原因

Between two protons the electrostatic repulsion exceeds the gravitational attraction by a factor of about $10^{36}$. Yet gravity governs planets, stars and galaxies. The resolution is sign: electric charge comes in $+$ and $-$, so bulk matter is almost perfectly neutral and its electric forces cancel over large scales. Mass has only one sign, so gravitational pulls always add up — never cancel. Over astronomical distances the relentless accumulation of a tiny force wins.

两个质子之间的静电斥力约为引力吸引的 $10^{36}$ 倍。然而引力主宰行星、恒星与星系。原因在于符号:电荷有 $+$、$-$ 两种,故宏观物质几乎完全中性,其电力在大尺度上相互抵消。质量只有一种符号,引力吸引总是叠加——从不抵消。在天文距离上,微小力的持续累积最终取胜。

This same sign argument explains why electric field lines can terminate (on the opposite charge) while gravitational field lines, having no "negative mass" to end on, only ever point inward toward mass.

同样的符号论证解释了:电场线可以终止(在相反电荷上),而引力场线因没有"负质量"可终止,只能指向质量向内。

Which property is shared by gravitational and electric fields but NOT by both being identical?引力场与电场共有、但并非使二者完全相同的性质是?
D2.6 · Q1
Both forces can be repulsive两种力都可以是斥力
Both obey an inverse-square law with distance两者都遵循随距离的平方反比律
Both act only on moving objects两者都只作用于运动物体
Both have sources of two signs两者的源都有两种符号
$F \propto 1/r^2$ for both gravity and the electric force — the shared inverse-square form. They differ in sign of source: mass is one sign (always attractive), charge is two signs (attract or repel).引力与电力都满足 $F \propto 1/r^2$——共有的平方反比形式。区别在源的符号:质量只有一种(恒吸引),电荷有两种(可吸可斥)。
Gravity is always attractive (mass has one sign) and acts on all matter at rest or moving. The genuine shared trait is the inverse-square distance law.引力恒为吸引(质量单一符号),且对静止或运动物体都起作用。真正共有的是平方反比的距离律。
Magnetic field lines differ fundamentally from gravitational and electric field lines because they:磁感线与引力场线、电场线的根本不同在于它们:
D2.6 · Q2
Form closed loops with no start or end point构成无起止点的闭合回路
Can cross one another可以彼此相交
Are always straight lines总是直线
Point only toward their source只指向其源
No magnetic monopoles exist, so magnetic field lines neither begin nor end — they are closed loops. Gravitational lines end on mass; electric lines start on $+$ and end on $-$.不存在磁单极子,故磁感线既不起也不止——是闭合回路。引力场线终止于质量;电场线起于 $+$、止于 $-$。
No type of field line crosses. The defining magnetic feature is the closed loop, a consequence of there being no magnetic monopole.任何场线都不相交。磁场的决定性特征是闭合回路,源于不存在磁单极子。

Exam Strategy and Common Pitfalls考试策略与常见陷阱

Units and powers of ten (every paper)单位与 10 的幂次(每张试卷)
  • Convert prefixes before substituting. $\mathrm{nC} \to 10^{-9}\ \mathrm{C}$, $\mu\mathrm{C} \to 10^{-6}\ \mathrm{C}$, $\mathrm{cm} \to 10^{-2}\ \mathrm{m}$. A missed factor of $10^{9}$ is the most common D.2 slip.
  • 代入前先换算前缀。$\mathrm{nC} \to 10^{-9}\ \mathrm{C}$、$\mu\mathrm{C} \to 10^{-6}\ \mathrm{C}$、$\mathrm{cm} \to 10^{-2}\ \mathrm{m}$。漏掉 $10^{9}$ 是 D.2 最常见的错误。
  • State magnitude and direction separately. Coulomb's law gives the size; you decide attract vs repel from the signs of the charges.
  • 大小与方向分开陈述。库仑定律给出大小;由电荷符号判定吸引还是排斥。
Field vs force vs potential场、力、势的区分
  • Don't confuse $E$ with $F$. $E = F/q$ is force per unit charge; it exists even where no test charge sits. Use $F = qE$ to get the actual force.
  • 别混淆 $E$ 与 $F$。$E = F/q$ 是单位电荷受力;即使没有检验电荷它也存在。用 $F = qE$ 求实际力。
  • Watch the power of $r$ HL. Field $E \propto 1/r^2$ but potential $V_e \propto 1/r$. Mixing these loses marks every year.
  • 注意 $r$ 的幂次 HL场 $E \propto 1/r^2$,电势 $V_e \propto 1/r$。混用每年都丢分。
Field-line and grip-rule sketches (Paper 2)场线与螺旋定则作图(Paper 2)
  • Add arrows. An unarrowed field-line sketch scores zero. Out of $+$, into $-$; N to S outside a magnet.
  • 必须画箭头。无箭头的场线图得零分。出 $+$、入 $-$;磁铁外部 N 到 S。
  • Keep parallel-plate lines straight, parallel and equally spaced. Bunching them implies a non-uniform field and loses the mark.
  • 平行板场线要笔直、平行、等间距。画密了暗示非匀强场,会丢分。
Synthesis questions (comparison)综合题(对比)
  • For "compare gravitational and electric fields", lead with the shared inverse-square form, then the sign difference (gravity attractive only).
  • 遇到"比较引力场与电场",先讲共有的平方反比形式,再讲符号差异(引力只吸引)。
  • For magnetic fields, the headline contrast is "closed loops, no monopole". Tie it to the field-line rules in your answer.
  • 对磁场,核心对比是"闭合回路、无单极子"。答题时与场线规则联系起来。

Flashcards闪卡

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Coulomb's law?库仑定律?
$$F = \frac{k q_1 q_2}{r^2}$$
Coulomb constant $k = ?$库仑常数 $k = ?$
$$k = \frac{1}{4\pi\varepsilon_0} \approx 8.99 \times 10^{9}\ \mathrm{N\,m^2\,C^{-2}}$$
Electric field strength definition?电场强度定义?
$$E = \frac{F}{q}$$Force per unit positive test charge.单位正检验电荷所受的力。
Radial field of a point charge?点电荷的径向场?
$$E = \frac{kQ}{r^2}$$
Uniform field between plates?平行板间匀强场?
$$E = \frac{V}{d}, \quad F = qE$$
Electric field-line rule (charges)?电场线规则(电荷)?
Out of $+$, into $-$; never cross.出 $+$、入 $-$;永不相交。
Conductor vs insulator?导体与绝缘体?
Conductor: free charges move. Insulator: charges bound.导体:自由电荷可动。绝缘体:电荷被束缚。
Electric potential? HL电势?HL
$$V_e = \frac{kQ}{r}$$
Electric PE of two charges? HL两电荷的电势能?HL
$$E_p = \frac{k q_1 q_2}{r}$$
Work to move charge between points? HL在两点间移动电荷做的功?HL
$$W = q\,\Delta V_e$$
Equipotential property? HL等势面性质?HL
$\perp$ field lines; no work to move along it.垂直于电场线;沿其移动不做功。
Right-hand grip rule (wire)?右手螺旋定则(导线)?
Thumb = current; curled fingers = $B$ direction.拇指 = 电流;弯曲四指 = $B$ 方向。
Magnetic field lines: start/end?磁感线:起止?
Closed loops; N to S outside a magnet. No monopole.闭合回路;磁铁外部 N 到 S。无单极子。
Gravity vs electric force: key difference?引力与电力的关键区别?
Same $1/r^2$ form; gravity attractive only, electric $\pm$.同为 $1/r^2$;引力只吸引,电力可吸可斥。

Unit D.2 Practice Quiz单元 D.2 练习测验

Two charges of $+2.0\ \mu\mathrm{C}$ and $+2.0\ \mu\mathrm{C}$ are $0.30\ \mathrm{m}$ apart in vacuum. The force between them ($k = 8.99 \times 10^{9}$) is approximately:真空中两个 $+2.0\ \mu\mathrm{C}$ 的电荷相距 $0.30\ \mathrm{m}$。它们之间的力($k = 8.99 \times 10^{9}$)约为:
Q1
$0.040\ \mathrm{N}$
$0.12\ \mathrm{N}$
$0.40\ \mathrm{N}$
$4.0\ \mathrm{N}$
$F = \dfrac{(8.99 \times 10^{9})(2.0 \times 10^{-6})^2}{(0.30)^2} = \dfrac{8.99 \times 10^{9} \times 4.0 \times 10^{-12}}{0.090} \approx 0.40\ \mathrm{N}$, repulsive (like charges).$F = \dfrac{(8.99 \times 10^{9})(2.0 \times 10^{-6})^2}{(0.30)^2} \approx 0.40\ \mathrm{N}$,相斥(同号)。
Convert $\mu\mathrm{C} \to 10^{-6}\ \mathrm{C}$, square the charge product, and divide by $r^2 = 0.090$. Result $\approx 0.40\ \mathrm{N}$.把 $\mu\mathrm{C} \to 10^{-6}\ \mathrm{C}$,对电荷乘积取值,再除以 $r^2 = 0.090$。结果约 $0.40\ \mathrm{N}$。
Parallel plates $5.0\ \mathrm{mm}$ apart have a $250\ \mathrm{V}$ potential difference. The field strength between them is:相距 $5.0\ \mathrm{mm}$ 的平行板电势差为 $250\ \mathrm{V}$。板间场强为:
Q2
$1.25 \times 10^{3}\ \mathrm{V\,m^{-1}}$
$5.0 \times 10^{4}\ \mathrm{V\,m^{-1}}$
$5.0 \times 10^{1}\ \mathrm{V\,m^{-1}}$
$1.25 \times 10^{6}\ \mathrm{V\,m^{-1}}$
$E = V/d = 250 / (5.0 \times 10^{-3}) = 5.0 \times 10^{4}\ \mathrm{V\,m^{-1}}$. The $\mathrm{mm} \to \mathrm{m}$ conversion is the trap.$E = V/d = 250 / (5.0 \times 10^{-3}) = 5.0 \times 10^{4}\ \mathrm{V\,m^{-1}}$。陷阱在 $\mathrm{mm} \to \mathrm{m}$ 换算。
$E = V/d$ with $d$ in metres: $5.0\ \mathrm{mm} = 5.0 \times 10^{-3}\ \mathrm{m}$. Dividing gives $5.0 \times 10^{4}\ \mathrm{V\,m^{-1}}$.$E = V/d$,$d$ 用米:$5.0\ \mathrm{mm} = 5.0 \times 10^{-3}\ \mathrm{m}$。相除得 $5.0 \times 10^{4}\ \mathrm{V\,m^{-1}}$。
A solenoid carries a steady current. To reverse which end is its north pole, you should:螺线管中通有稳恒电流。要使其北极端互换,应该:
Q3
Increase the current增大电流
Add more turns to the coil增加线圈匝数
Insert an iron core插入铁芯
Reverse the direction of the current反转电流方向
The pole identity is set by the current direction via the right-hand grip rule. Reversing the current swaps N and S. Increasing current, turns, or adding iron only changes the field's strength.极性由电流方向经右手螺旋定则决定。反转电流即互换 N、S。增大电流、增加匝数或加铁芯只改变场的强度
Strength changes (more current/turns/iron core) do not flip the poles. Only reversing the current direction swaps N and S.增强(更大电流/更多匝/铁芯)不会翻转磁极。只有反转电流方向才互换 N、S。
HL An electron is moved from a point at potential $-50\ \mathrm{V}$ to a point at $+100\ \mathrm{V}$. The work done on the electron ($e = 1.60 \times 10^{-19}\ \mathrm{C}$) is approximately:HL 把一个电子从电势 $-50\ \mathrm{V}$ 处移到 $+100\ \mathrm{V}$ 处。对电子所做的功($e = 1.60 \times 10^{-19}\ \mathrm{C}$)约为:
Q4
$-2.4 \times 10^{-17}\ \mathrm{J}$
$+2.4 \times 10^{-17}\ \mathrm{J}$
$-8.0 \times 10^{-18}\ \mathrm{J}$
$+1.6 \times 10^{-17}\ \mathrm{J}$
$W = q\,\Delta V_e$ with $q = -e$ and $\Delta V_e = 100 - (-50) = 150\ \mathrm{V}$. $W = (-1.60 \times 10^{-19})(150) = -2.4 \times 10^{-17}\ \mathrm{J}$. Negative: the field does the moving for a negative charge climbing to higher potential.$W = q\,\Delta V_e$,$q = -e$、$\Delta V_e = 100 - (-50) = 150\ \mathrm{V}$。$W = (-1.60 \times 10^{-19})(150) = -2.4 \times 10^{-17}\ \mathrm{J}$。为负:负电荷升向高电势时场代为做功。
Use $W = q\,\Delta V_e$ with the electron's sign $q = -e$ and $\Delta V_e = +150\ \mathrm{V}$. The product is negative: $-2.4 \times 10^{-17}\ \mathrm{J}$.用 $W = q\,\Delta V_e$,电子取 $q = -e$、$\Delta V_e = +150\ \mathrm{V}$。乘积为负:$-2.4 \times 10^{-17}\ \mathrm{J}$。
A student claims all three field types (gravitational, electric, magnetic) share the same field-line "start and end" behaviour. The correct objection is:某学生声称三种场(引力、电、磁)的场线"起止"行为相同。正确的反驳是:
Q5
Electric lines form closed loops, unlike the others电场线构成闭合回路,与其他不同
Magnetic lines form closed loops, while gravitational and electric lines start/end on their source charges磁感线构成闭合回路,而引力与电场线起止于其源
Gravitational lines can cross, the others cannot引力场线可相交,其他不可
All three actually behave identically; the student is right三者实际相同,学生是对的
Gravitational lines end on mass and electric lines run from $+$ to $-$ — both terminate on sources. Magnetic lines are different: with no monopole, they form closed loops with no start or end.引力场线终止于质量,电场线由 $+$ 到 $-$——都终止于源。磁感线不同:无单极子,故为无起止的闭合回路。
The odd one out is magnetic: its lines are closed loops (no monopole). Gravitational and electric lines start/end on their sources. None cross.特殊的是磁场:其场线为闭合回路(无单极子)。引力与电场线起止于源。三者都不相交。

Readiness Checklist备考清单

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