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Homeostasis · Solutions稳态 · 详解

Companion to the Practice Set · Mark-by-mark walkthroughs · AP-Feeder / ON / BC / AB styles练习题配套答案 · 逐分讲解 · AP 衔接 / 安 / 卑 / 阿省考风格

EASY MEDIUM HARD 🇺🇸 US 🇨🇦 ON 🇨🇦 BC 🇨🇦 AB AP-style MCQAP 风格选择题 AP-feeder FRQAP 衔接简答题 ON Provincial-style安大略省考风格 BC Provincial-style卑诗省考风格 AB Diploma-style阿尔伯塔毕业考风格 Honors荣誉级


PART I  ·  SHORT RESPONSE · SOLUTIONS第一部分  ·  短答题 · 详解AP MCQ + ON/BC short answer · 22 marksAP 选择题 + 安/卑省考短答 · 共 22 分

Section A · Worked SolutionsA 部分 · 详细解答

Q1EASY 🇺🇸 US AP-style MCQAP 风格选择题 §1 Homeostasis稳态 · HS-LS1-3 [3 marks][3 分]

Which of the following best defines homeostasis?以下哪项最能准确定义稳态?

Answer:答案:  (A) The maintenance of a stable internal environment despite changes in external conditions在外部条件变化的情况下维持稳定的内部环境

Why (A) is correct为何选 (A) K1·U1·U1

Homeostasis is the process by which living organisms regulate their internal conditions (temperature, blood glucose, water balance, etc.) within a narrow, stable range, even when the external environment changes. Option (A) captures both the internal target (stable internal environment) and the challenge (external changes).稳态是生物体将内部条件(体温、血糖、水分平衡等)维持在一个狭窄稳定范围内的过程,即使外部环境发生变化也如此。选项 (A) 同时涵盖了内部目标(稳定的内部环境)和外部挑战(外界变化)。
Why the distractors fail.干扰项分析。
(B): describes evolutionary adaptation across generations, not real-time physiological regulation.描述的是跨代进化适应,而非实时的生理调节。
(C): describes osmosis or diffusion equilibrium, not the broader concept of homeostasis.描述的是渗透或扩散平衡,而非稳态的广义概念。
(D): describes gene regulation, which may be one mechanism but is not the definition of homeostasis.描述的是基因调控,这可能是稳态机制之一,但并非稳态的定义。
Homeostasis requires three components: a sensor (receptor), a control centre, and an effector.稳态需要三个组成部分:感受器、控制中枢和效应器。 The word "homeostasis" literally means "staying the same" (Greek: homoios + stasis). However, the internal environment is not truly constant; it fluctuates around a set point. The biological set point acts like a thermostat target temperature. When a variable drifts outside the acceptable range, a negative feedback loop activates: the sensor detects the change, the control centre processes the signal, and the effector corrects the deviation. This three-part framework (receptor, control centre, effector) is essential for answering any homeostasis question on AP, ON, BC, and AB exams."稳态"一词字面意思是"保持相同"(希腊语:homoios + stasis)。然而内部环境并非真正恒定,而是在调定点附近波动。生物调定点就像恒温器的目标温度。当某变量偏离可接受范围时,负反馈回路被激活:感受器检测变化,控制中枢处理信号,效应器纠正偏差。这一三部分框架(感受器、控制中枢、效应器)对于回答 AP、安大略、卑诗和阿尔伯塔考试中任何稳态题目都至关重要。
Q2EASY 🇨🇦 ON ON Provincial-style安大略省考风格 §2 Thermoregulation体温调节 · SBI4U C1 [4 marks][4 分]

A person stands outside on a cold winter day. Describe two physiological responses that help maintain core body temperature, and identify whether each is a mechanism for reducing heat loss or generating additional heat.一个人站在寒冷的冬日室外。描述两种帮助维持核心体温的生理反应,并说明每种反应是减少热量散失还是产生额外热量的机制。

Answer: (1) Vasoconstriction of skin blood vessels (reduces heat loss); (2) Shivering of skeletal muscles (generates additional heat)答案:(1) 皮肤血管收缩(减少热量散失);(2) 骨骼肌颤抖(产生额外热量)

Response 1: Vasoconstriction (reduces heat loss)反应 1:血管收缩(减少热量散失) K1·U1

When core temperature drops, the hypothalamus signals arterioles near the skin surface to constrict. This reduces blood flow to the skin, keeping warm blood in the body core and minimising heat transfer to the cold environment. The skin may appear pale or bluish.当核心体温下降时,下丘脑向皮肤表面附近的小动脉发出收缩信号。这减少了流向皮肤的血液,将温热血液保留在身体核心,并将向寒冷环境的热量传递降到最低。皮肤可能呈现苍白或略带蓝色。

Response 2: Shivering (generates additional heat)反应 2:颤抖(产生额外热量) K1·U1

The hypothalamus also triggers rapid, involuntary contractions of skeletal muscles (shivering). These repeated contractions increase the rate of cellular respiration in muscle tissue, releasing heat as a byproduct that warms the body from within. Shivering can increase the metabolic heat production rate several-fold.下丘脑还会触发骨骼肌快速、不自主的收缩(颤抖)。这些重复收缩增加了肌肉组织的细胞呼吸速率,将热量作为副产品释放出来,从内部加热身体。颤抖可使代谢产热速率提高数倍。
Cold responses fall into two categories: reducing heat loss (insulation/vasoconstriction/piloerection) and increasing heat production (shivering/non-shivering thermogenesis).御寒反应分为两类:减少热量散失(绝热/血管收缩/竖毛)和增加产热(颤抖/非颤抖产热)。 Other acceptable responses include: piloerection (hair standing on end, trapping an insulating air layer) which reduces heat loss, or non-shivering thermogenesis in brown adipose tissue (more prominent in newborns and hibernating animals) which generates heat. For exam purposes, always classify each response as either reducing heat loss or increasing heat generation, and name the tissue or structure involved.其他可接受的答案包括:竖毛(汗毛竖立,形成绝热空气层)可减少热量散失,或棕色脂肪组织中的非颤抖产热(在新生儿和冬眠动物中更为突出)可产生热量。在考试中,务必将每种反应归类为减少热量散失或增加产热,并指明所涉及的组织或结构。
Q3MEDIUM 🇺🇸 US AP-style MCQAP 风格选择题 §4 Blood glucose regulation血糖调节 · HS-LS1-3 [3 marks][3 分]

After a large meal, blood glucose concentration rises. Which response correctly describes the pancreatic response and its effect?大量进食后,血糖浓度升高。以下哪项正确描述了胰腺的反应及其效果?

Answer:答案:  (B) Beta cells secrete insulin, stimulating glucose uptake by cells and glycogen synthesis in the liver胰岛 beta 细胞分泌胰岛素,刺激细胞摄取葡萄糖并在肝脏中合成糖原

Why (B) is correct为何选 (B) K1·U1·U1

When blood glucose rises above the set point (approximately $4.0$-$6.0\ \text{mmol/L}$), beta cells in the islets of Langerhans of the pancreas detect the change and secrete insulin. Insulin acts on body cells to increase glucose uptake via GLUT4 transporters, and signals the liver to convert excess glucose into glycogen (glycogenesis). Both effects lower blood glucose back toward the set point.当血糖升至调定点(约 $4.0$-$6.0\ \text{mmol/L}$)以上时,胰腺朗格汉斯岛中的 beta 细胞检测到这一变化并分泌胰岛素。胰岛素作用于体细胞,通过 GLUT4 转运蛋白增加葡萄糖摄取,并向肝脏发出信号将多余葡萄糖转化为糖原(糖原合成)。这两种效应都使血糖向调定点降低。
Why the distractors fail.干扰项分析。
(A): alpha cells secrete glucagon (not the response to high glucose); glucagon raises, not lowers, blood glucose.alpha 细胞分泌胰高血糖素(不是对高血糖的反应);胰高血糖素会升高血糖,而非降低。
(C): beta cells are correct but glucagon is wrong; beta cells never secrete glucagon.beta 细胞正确,但胰高血糖素错误;beta 细胞从不分泌胰高血糖素。
(D): alpha cells secrete glucagon (not insulin); releasing glucose from the liver would worsen hyperglycaemia.alpha 细胞分泌胰高血糖素(而非胰岛素);从肝脏释放葡萄糖会加重高血糖。
Memory anchor: Beta cells release insulin (B for "Below set point means glucagon, Above means insulin" is backwards; instead: Beta-Insulin pair, Alpha-Glucagon pair).记忆锚点:Beta 细胞释放胰岛素,Alpha 细胞释放胰高血糖素。 The classic pairing is: Beta cells + Insulin = lower blood glucose (after eating); Alpha cells + Glucagon = raise blood glucose (during fasting or exercise). A useful check: insulin and "in" rhyme, and insulin drives glucose into cells. Glucagon and "gone" hint that glucose stored as glycogen is broken "gone" free again. Both are negative feedback loops around the blood-glucose set point.经典配对是:Beta 细胞 + 胰岛素 = 降低血糖(餐后);Alpha 细胞 + 胰高血糖素 = 升高血糖(空腹或运动时)。一个有用的记忆:胰岛素(insulin)促使葡萄糖进入(in)细胞。两者都是围绕血糖调定点的负反馈回路。
Q4MEDIUM 🇨🇦 BC BC Provincial-style卑诗省考风格 §1 Feedback loops反馈回路 · Biology 12 [6 marks][6 分]

Compare negative feedback and positive feedback in homeostasis.比较稳态中的负反馈与正反馈。

Answer: (a) Negative feedback reverses the change (e.g. thermoregulation); (b) Positive feedback amplifies the change (e.g. childbirth); (c) Negative feedback is self-limiting and restores the set point答案:(a) 负反馈逆转变化(如体温调节);(b) 正反馈放大变化(如分娩);(c) 负反馈具有自限性并恢复调定点

(a) Negative feedback: defining feature and example负反馈:核心特征与实例 K1·U1

Defining feature: the response opposes (reverses) the original stimulus, returning the variable toward the set point. Example: when body temperature rises above $37\ ^\circ\text{C}$, sweating and vasodilation cool the body, reducing the original stimulus. When temperature falls, shivering and vasoconstriction warm it, again countering the change.核心特征:反应对抗(逆转)原始刺激,将变量拉回调定点。实例:当体温升至 $37\ ^\circ\text{C}$ 以上时,出汗和血管舒张使体温下降,减弱原始刺激。当体温下降时,颤抖和血管收缩使体温升高,同样对抗变化。

(b) Positive feedback: defining feature and example正反馈:核心特征与实例 K1·U1

Defining feature: the response amplifies the original stimulus, pushing the variable further from the starting point until a specific endpoint is reached. Example: during childbirth, the baby's head pressing on the cervix triggers oxytocin release, which intensifies contractions, which press harder on the cervix, releasing more oxytocin. This cycle continues until the baby is delivered (the endpoint terminates the loop).核心特征:反应放大原始刺激,将变量进一步推离起点,直到达到特定终点。实例:分娩时,胎儿头部压迫宫颈触发催产素释放,加剧宫缩,宫缩更强力压迫宫颈,释放更多催产素。这一循环持续至胎儿娩出(终点终止回路)。

(c) Why homeostasis relies on negative feedback为何稳态依赖负反馈 U1·U1

Negative feedback is self-limiting: once the variable returns to the set point, the corrective response stops. This creates a stable equilibrium around the set point. Positive feedback is self-amplifying: it drives the system away from the set point. If used for routine regulation, positive feedback would cause runaway changes that could be lethal. Therefore, positive feedback is reserved for events that must proceed rapidly to completion (childbirth, blood clotting, the nerve action potential), not for maintaining a stable internal state.负反馈具有自限性:一旦变量回到调定点,纠正反应就会停止。这在调定点周围形成稳定平衡。正反馈具有自我放大性:它推动系统偏离调定点。如果用于常规调节,正反馈会导致失控的变化,可能是致命的。因此,正反馈仅用于必须迅速完成的事件(分娩、血液凝固、神经动作电位),而不用于维持稳定的内部状态。
Negative feedback = stability; positive feedback = rapid completion of a process.负反馈 = 稳定性;正反馈 = 快速完成某一过程。 A common exam error is to say that positive feedback "disrupts homeostasis" in a purely negative way. The key insight is that positive feedback serves a biological purpose but that purpose is never sustained steady-state regulation. Any feedback loop question should prompt you to ask: does the response diminish or amplify the original change? Diminish = negative feedback; amplify = positive feedback. Always tie your answer to a named biological example for full marks on BC Provincial and AB Diploma exams.一个常见的考试错误是说正反馈"破坏稳态",将其视为纯粹的负面现象。关键洞见是:正反馈有其生物学目的,但该目的绝不是持续的稳态调节。面对任何反馈回路题目,都应该问:反应是减弱还是放大了原始变化?减弱 = 负反馈;放大 = 正反馈。在卑诗省考和阿尔伯塔毕业考中,务必结合具体生物学实例作答以获满分。
Q5MEDIUM 🇨🇦 AB AB Diploma-style阿尔伯塔毕业考风格 §3 Osmoregulation渗透调节 · Biology 30 30-C2.1k [6 marks][6 分]

A person drinks a large volume of water rapidly, causing blood osmolarity to decrease below the set point.一个人快速大量饮水,导致血液渗透压降低至调定点以下。

Answer: (a) Osmoreceptors in the hypothalamus; (b) ADH secretion decreases, urine volume increases; (c) more water is excreted, restoring blood osmolarity toward the set point答案:(a) 下丘脑中的渗透压感受器;(b) ADH 分泌减少,尿量增加;(c) 排出更多水分,使血液渗透压向调定点恢复

(a) Receptor and location感受器及其位置 K1·K1

The receptor is osmoreceptors (specialised hypothalamic neurons) located in the hypothalamus of the brain. These cells contain stretch-sensitive ion channels that detect changes in their own volume caused by shifts in the surrounding fluid osmolarity. When blood osmolarity falls, water moves into the osmoreceptor cells by osmosis, causing them to swell, which reduces the signal to release ADH.感受器是位于大脑下丘脑的渗透压感受器(特化的下丘脑神经元)。这些细胞含有牵张敏感的离子通道,可检测周围液体渗透压变化引起的自身体积变化。当血液渗透压下降时,水通过渗透作用进入渗透压感受器细胞,使其膨胀,从而减少释放 ADH 的信号。

(b) ADH changes and consequence for urineADH 变化及对尿液的影响 U1·U1

ADH (antidiuretic hormone, also called vasopressin) secretion decreases. With less ADH circulating, the collecting ducts of the kidney become less permeable to water (fewer aquaporin channels are inserted). Less water is reabsorbed from the filtrate, so urine volume increases and urine becomes more dilute.ADH(抗利尿激素,又称加压素)分泌减少。随着循环中 ADH 减少,肾脏集合管对水的通透性降低(插入的水通道蛋白数量减少)。从滤液中重吸收的水减少,因此尿量增加,尿液变得更稀。

(c) How the response restores blood osmolarity该反应如何恢复血液渗透压 U1·U1

By producing large volumes of dilute urine, the kidneys remove the excess water from the body. This reduces the water content of the blood, increasing its solute concentration back toward the set point (approximately $285$-$295\ \text{mOsm/kg}$). The osmoreceptors detect the rising osmolarity and reduce the inhibitory signal, allowing ADH secretion to stabilise at its baseline level. This is a classic negative feedback loop: the deviation (low osmolarity) triggers a response (more dilute urine) that reverses the deviation.通过产生大量稀尿,肾脏将多余的水从体内排出。这降低了血液中的水含量,使溶质浓度升回调定点(约 $285$-$295\ \text{mOsm/kg}$)。渗透压感受器检测到升高的渗透压,减少抑制信号,使 ADH 分泌稳定在基线水平。这是一个经典的负反馈回路:偏差(渗透压低)触发反应(更多稀尿),逆转偏差。
ADH is the key hormone of osmoregulation: high osmolarity causes more ADH and concentrated urine; low osmolarity causes less ADH and dilute urine.ADH 是渗透调节的关键激素:高渗透压导致 ADH 增多和浓缩尿;低渗透压导致 ADH 减少和稀尿。 The phrase "antidiuretic" means "against excessive urination": ADH reduces urine output. When osmolarity is low (too much water), the body needs to get rid of water, so ADH decreases and urine output rises. When osmolarity is high (dehydrated), the body needs to retain water, so ADH increases and urine output falls. This bidirectional control around the osmolarity set point is a textbook example of negative feedback. The AB Biology 30 diploma exam frequently pairs this with a data table of urine concentration versus ADH level, so always know the direction of each effect."抗利尿"的意思是"对抗过量排尿":ADH 减少尿液输出。当渗透压低(水分过多)时,身体需要排出水分,ADH 减少,尿量增加。当渗透压高(脱水)时,身体需要保留水分,ADH 增加,尿量减少。这种围绕渗透压调定点的双向控制是负反馈的教科书式范例。阿省生物 30 毕业考经常将此与尿液浓度对 ADH 水平的数据表配对出题,因此务必掌握每种效应的方向。
PART II  ·  EXTENDED RESPONSE · SOLUTIONS第二部分  ·  简答题 · 详解AP-feeder FRQ + honors · 32 marksAP 衔接简答题 + 荣誉级 · 共 32 分

Section B · Worked SolutionsB 部分 · 详细解答

Q6MEDIUM 🇺🇸 US AP-feeder FRQAP 衔接简答题 §1 + §2 Feedback loop / thermoregulation反馈回路 / 体温调节 · HS-LS1-3 [8 marks][8 分]

Core body temperature rises above $37\ ^\circ\text{C}$ during vigorous exercise.剧烈运动期间,核心体温升至 $37\ ^\circ\text{C}$ 以上。

Answer: (a) Thermoreceptors / hypothalamus; (b) sweating + vasodilation (2 marks each); (c) thermoreceptors detect return to set point, hypothalamus stops sending corrective signals答案:(a) 温度感受器 / 下丘脑;(b) 出汗 + 血管舒张(各 2 分);(c) 温度感受器检测到恢复调定点,下丘脑停止发送纠正信号

(a) Receptor and control centre感受器与控制中枢 K1·K1

Receptor: peripheral thermoreceptors in the skin and central thermoreceptors in the hypothalamus detect the rise in temperature. Control centre: the hypothalamus (specifically the anterior hypothalamus) integrates the temperature signals and coordinates the cooling response.感受器:皮肤中的外周温度感受器和下丘脑中的中枢温度感受器检测到温度升高。控制中枢:下丘脑(特别是前下丘脑)整合温度信号并协调降温反应。

(b) Two effector responses and their mechanisms两种效应器反应及其机制 U1·U1·U1·U1

Response 1: Sweating. Sweat glands (effectors) are activated by the hypothalamus via the sympathetic nervous system. Sweat (mostly water) spreads over the skin surface. As sweat evaporates, it absorbs latent heat of vaporisation from the skin, cooling the body. The higher the rate of sweating, the greater the cooling effect.反应 1:出汗。 下丘脑通过交感神经系统激活汗腺(效应器)。汗液(主要是水)在皮肤表面扩散。汗液蒸发时从皮肤吸收汽化潜热,使身体降温。出汗速率越高,降温效果越强。
Response 2: Vasodilation of skin arterioles. The hypothalamus signals smooth muscle in skin arterioles to relax, widening the vessels. More warm blood from the body core flows to the skin surface, where heat is lost to the cooler environment by radiation and convection. The skin may appear flushed or red.反应 2:皮肤小动脉舒张。 下丘脑向皮肤小动脉的平滑肌发出松弛信号,使血管舒张。更多来自体核的温热血液流向皮肤表面,通过辐射和对流将热量散发到较凉的环境中。皮肤可能呈现潮红。

(c) Completion of the feedback loop反馈回路的完成 U1·U1

As sweating and vasodilation dissipate heat, body temperature falls back toward $37\ ^\circ\text{C}$. The thermoreceptors in the hypothalamus and skin detect that temperature has returned to the set point. The hypothalamus receives this updated signal and reduces or stops the nerve impulses to sweat glands and skin arterioles. Sweating decreases and vasodilation reverses. The loop is complete because the response (cooling) has eliminated the stimulus (elevated temperature), so no further correction is needed.随着出汗和血管舒张散热,体温回落至 $37\ ^\circ\text{C}$。下丘脑和皮肤中的温度感受器检测到体温已回到调定点。下丘脑接收到这一更新信号,减少或停止向汗腺和皮肤小动脉发送神经冲动。出汗减少,血管舒张逆转。回路完成,因为反应(降温)已消除刺激(体温升高),不再需要进一步纠正。
The feedback loop has four steps: stimulus (high temperature) - receptor (thermoreceptors) - control centre (hypothalamus) - effector (sweat glands / arterioles) - response (cooling) - back to set point.反馈回路有四个步骤:刺激(体温高)- 感受器(温度感受器)- 控制中枢(下丘脑)- 效应器(汗腺/小动脉)- 反应(降温)- 回到调定点。 On AP Biology and AP Environmental Science free-response questions, examiners expect you to use the specific terms "receptor," "control centre," and "effector" and to state how each connects. Sweating works best in low humidity (water evaporates easily); in high humidity it is less effective because the air is already saturated. Athletes in humid environments are at greater risk of heat stroke because their cooling mechanism is compromised. This real-world application often appears as a context in AP data analysis questions.在 AP 生物和 AP 环境科学的简答题中,评卷人期望你使用"感受器"、"控制中枢"和"效应器"等专业术语,并说明各部分的连接方式。出汗在低湿度环境中效果最好(水分易蒸发);在高湿度环境中效果较差,因为空气已经饱和。潮湿环境中的运动员面临更大的中暑风险,因为其降温机制受损。这一实际应用常作为 AP 数据分析题的情境出现。
Q7MEDIUM 🇨🇦 ON ON Provincial-style安大略省考风格 §4 Blood glucose regulation血糖调节 · SBI4U C2 [8 marks][8 分]

Blood glucose regulation is a key example of homeostasis in humans.血糖调节是人体稳态的关键实例。

Answer: (a) Insulin / beta cells / glycogen synthesis + cell glucose uptake; (b) glucagon / alpha cells / glycogenolysis; (c) blood glucose stays high because no insulin to drive glucose into cells答案:(a) 胰岛素 / beta 细胞 / 糖原合成 + 细胞摄取葡萄糖;(b) 胰高血糖素 / alpha 细胞 / 糖原分解;(c) 血糖持续偏高,因为没有胰岛素驱动葡萄糖进入细胞

(a) Pancreatic response to high blood glucose胰腺对高血糖的反应 K1·K1·U1·U1

Hormone: insulin. Cell type: beta cells (in the islets of Langerhans). Target effect 1: insulin stimulates body cells (especially muscle and fat cells) to increase glucose uptake via GLUT transporters, reducing blood glucose. Target effect 2: insulin signals the liver to convert glucose into glycogen (glycogenesis), storing excess glucose and further lowering blood glucose concentration.激素:胰岛素。细胞类型:beta 细胞(朗格汉斯岛中)。靶效应 1:胰岛素刺激体细胞(尤其是肌肉和脂肪细胞)通过 GLUT 转运蛋白增加葡萄糖摄取,降低血糖。靶效应 2:胰岛素向肝脏发出信号,将葡萄糖转化为糖原(糖原合成),储存多余葡萄糖,进一步降低血糖浓度。

(b) Pancreatic response to low blood glucose胰腺对低血糖的反应 K1·U1

Hormone: glucagon. Cell type: alpha cells (in the islets of Langerhans). Target effect: glucagon signals the liver to break down glycogen into glucose (glycogenolysis) and to synthesise new glucose from amino acids (gluconeogenesis). Both effects release glucose into the blood, raising blood glucose back toward the set point.激素:胰高血糖素。细胞类型:alpha 细胞(朗格汉斯岛中)。靶效应:胰高血糖素向肝脏发出信号,分解糖原为葡萄糖(糖原分解)并从氨基酸合成新葡萄糖(糖异生)。两种效应都将葡萄糖释放入血,使血糖向调定点升高。

(c) Type 1 diabetes: prediction and explanation1 型糖尿病:预测与解释 U1·U1

Prediction: blood glucose will rise significantly after a meal and remain elevated (hyperglycaemia). Explanation: without insulin, body cells cannot efficiently take up glucose from the blood (GLUT4 transporters are not activated), and the liver does not convert glucose to glycogen. Glucose from digested food accumulates in the bloodstream. The negative feedback loop is broken because the effector response (insulin) is absent, so the deviation from the set point cannot be corrected.预测:餐后血糖将显著升高并持续偏高(高血糖症)。解释:没有胰岛素,体细胞无法有效从血液中摄取葡萄糖(GLUT4 转运蛋白未被激活),肝脏也不将葡萄糖转化为糖原。消化食物中的葡萄糖在血流中积聚。负反馈回路被打断,因为效应器反应(胰岛素)缺失,偏差无法被纠正。
Blood glucose regulation is a dual-hormone negative feedback system: insulin lowers glucose; glucagon raises glucose.血糖调节是一个双激素负反馈系统:胰岛素降低血糖;胰高血糖素升高血糖。 Type 1 diabetes (autoimmune destruction of beta cells) is the classic example of what happens when one half of the dual feedback system fails. Without insulin, glucose cannot enter most cells, so cells switch to burning fatty acids, producing ketone bodies as a byproduct. If ketones accumulate too fast, blood pH drops (diabetic ketoacidosis), which is a medical emergency. Type 2 diabetes is a different failure mode: beta cells still produce insulin but target cells become insulin-resistant. Both conditions disrupt the negative feedback loop, but through different mechanisms. Examiners in ON and AB frequently test the distinction.1 型糖尿病(beta 细胞的自身免疫性破坏)是双反馈系统一半失效时的经典范例。没有胰岛素,葡萄糖无法进入大多数细胞,细胞转而燃烧脂肪酸,产生酮体作为副产品。若酮体积聚过快,血液 pH 下降(糖尿病酮症酸中毒),这是医疗紧急情况。2 型糖尿病是不同的失效模式:beta 细胞仍产生胰岛素,但靶细胞产生胰岛素抵抗。两种情况都破坏了负反馈回路,但机制不同。安大略和阿尔伯塔的考试经常测试这一区别。
Q12HARD 🇺🇸 US AP-feeder FRQAP 衔接简答题 §2 + §7 Thermoregulation and system integration (applied)体温调节与系统整合(应用) · HS-LS1-3 [10 marks][10 分]

A researcher studies two individuals: Person A (an ectotherm, such as a lizard) and Person B (an endotherm, such as a human). Both are exposed to an environmental temperature of $10\ ^\circ\text{C}$.一名研究者研究两类个体:甲(外温动物,如蜥蜴)和乙(内温动物,如人类)。两者均暴露于 $10\ ^\circ\text{C}$ 的环境温度下。

Answer: (a) Person A cools toward 10 C (no internal heat); Person B maintains ~37 C (active thermoregulation); (b) vasoconstriction, shivering, piloerection; (c) endothermy advantage = activity in cold; cost = high metabolic energy demand答案:(a) 甲体温趋向 10 C(无内部产热);乙维持约 37 C(主动体温调节);(b) 血管收缩、颤抖、竖毛;(c) 内温性优势 = 寒冷中保持活动;代价 = 高代谢能量需求

(a) Core temperature predictions and justifications核心体温预测与依据 U1·U1·U1·U1

Person A (ectotherm): Core body temperature will drop toward $10\ ^\circ\text{C}$ over 30 minutes. Justification: ectotherms (also called poikilotherms or "cold-blooded" animals) rely on external heat sources to warm their bodies and do not generate significant metabolic heat internally. At $10\ ^\circ\text{C}$, heat flows from the warmer body to the cooler environment, and without an internal heat source, body temperature equilibrates with the surroundings. The lizard's enzymatic activity and movement will slow dramatically.甲(外温动物):核心体温将在 30 分钟内降至接近 $10\ ^\circ\text{C}$。依据:外温动物(也称变温动物或"冷血"动物)依赖外部热源来温暖身体,不在内部产生显著的代谢热量。在 $10\ ^\circ\text{C}$ 时,热量从较温暖的身体流向较凉的环境,没有内部热源,体温与周围环境达到平衡。蜥蜴的酶活性和运动将大幅减慢。
Person B (endotherm): Core body temperature will remain near $37\ ^\circ\text{C}$ after 30 minutes. Justification: endotherms (also called homeotherms or "warm-blooded" animals) generate heat internally through cellular respiration (primarily in muscle and liver tissue) and use physiological mechanisms such as vasoconstriction and shivering to maintain a constant body temperature regardless of the external temperature. The hypothalamus acts as the thermostat, detecting the temperature drop and activating corrective responses.乙(内温动物):核心体温在 30 分钟后将保持在约 $37\ ^\circ\text{C}$。依据:内温动物(也称恒温动物或"温血"动物)通过细胞呼吸(主要在肌肉和肝脏组织中)在内部产生热量,并利用血管收缩和颤抖等生理机制在外部温度变化时维持恒定体温。下丘脑作为恒温器,检测到温度下降并激活纠正反应。

(b) Three physiological mechanisms for cold tolerance in Person B乙在寒冷中的三种生理机制 K1·K1·K1

Mechanism 1: Vasoconstriction of skin arterioles. Category: reduces heat loss. By narrowing skin blood vessels, less warm blood reaches the skin surface, reducing heat transfer to the environment by radiation and conduction.机制 1:皮肤小动脉收缩。类别:减少热量散失。通过收缩皮肤血管,较少的温热血液到达皮肤表面,减少通过辐射和传导向环境传递的热量。
Mechanism 2: Shivering of skeletal muscles. Category: increases heat production. Rapid involuntary muscle contractions generate heat as a byproduct of ATP hydrolysis in muscle tissue, warming the body from the inside.机制 2:骨骼肌颤抖。类别:增加产热。快速不自主的肌肉收缩作为肌肉组织中 ATP 水解的副产品产生热量,从内部温暖身体。
Mechanism 3: Piloerection (goosebumps). Category: reduces heat loss. Arrector pili muscles contract, raising skin hairs and trapping a layer of warm air next to the skin surface, which acts as additional insulation. In humans with sparse body hair this effect is small, but in furry mammals it is a primary insulation mechanism.机制 3:竖毛(鸡皮疙瘩)。类别:减少热量散失。竖毛肌收缩,使皮肤毛发竖起,在皮肤表面附近形成一层温暖空气,起到额外的绝热作用。在体毛稀疏的人类中这种效应较小,但在多毛哺乳动物中是主要的绝热机制。

(c) Advantage and cost (trade-off) of endothermy in a cold environment寒冷环境中内温性的优势与代价(权衡) U1·U1·U1

Advantage: endotherms can remain active in cold environments because their enzyme kinetics, nerve conduction, and muscle contraction operate at a stable high temperature. This allows them to hunt, forage, and escape predators year-round, even in winter. Ectotherms such as lizards become sluggish or dormant in cold conditions, making them vulnerable.优势:内温动物在寒冷环境中能保持活跃,因为其酶动力学、神经传导和肌肉收缩在稳定的高温下运作。这使它们能够全年(包括冬季)进行狩猎、觅食和逃避天敌。外温动物如蜥蜴在寒冷条件下变得迟钝或进入休眠,使其更易受攻击。
Cost (trade-off): endothermy requires a very high metabolic rate to sustain constant body heat. Endotherms must consume far more food per unit body mass than ectotherms of the same size, even when resting. Approximately $80$-$90\%$ of the calories an endotherm consumes are used just to maintain body temperature. This makes endotherms more vulnerable to food scarcity and requires them to spend much more time foraging. An ectotherm of the same body mass requires roughly $5$-$10$ times less food energy to survive.代价(权衡):内温性需要非常高的代谢率来维持恒定体温。内温动物每单位体重消耗的食物远多于同等大小的外温动物,即使在休息时也是如此。内温动物消耗的约 $80$-$90\%$ 的卡路里仅用于维持体温。这使内温动物更容易受到食物匮乏的影响,需要花费更多时间觅食。同等体重的外温动物生存所需食物能量大约少 $5$-$10$ 倍。
Endothermy = metabolic independence from the environment; ectothermy = metabolic efficiency at the cost of activity in the cold.内温性 = 代谢上独立于环境;外温性 = 以牺牲寒冷中的活动能力为代价换取代谢效率。 This trade-off is a central concept in evolutionary biology and ecology. AP Biology exam questions on thermoregulation often present a graph of metabolic rate versus environmental temperature for an ectotherm and an endotherm: the endotherm's metabolic rate increases sharply in the cold (to compensate for heat loss), while the ectotherm's metabolic rate falls with temperature (because enzyme activity slows). The cross-over point where the two curves intersect represents the temperature at which both strategies have the same metabolic cost. Below that temperature, ectothermy is more efficient; above it (in warm environments), ectothermy is also more efficient because the animal needs less energy to maintain body temperature. Endothermy is never metabolically cheaper, but it confers the ecological advantage of environmental independence.这一权衡是进化生物学和生态学中的核心概念。AP 生物考试中关于体温调节的题目经常呈现外温动物和内温动物的代谢率对比环境温度的图表:内温动物的代谢率在寒冷中急剧增加(以补偿热量损失),而外温动物的代谢率随温度下降(因为酶活性减慢)。两条曲线相交的交叉点代表两种策略代谢成本相同的温度。低于该温度,外温性更高效;高于该温度(在温暖环境中),外温性也更高效,因为动物维持体温所需能量较少。内温性在代谢上从不更便宜,但赋予了环境独立性的生态优势。