Show all supporting work on scratch paper. Each item is labeled with its Mechanics topic and whether a calculator is permitted on that AP Exam section.请将解题过程写在草稿纸上。每题均标注了对应的力学专题及该 AP 考试部分是否允许使用计算器。
Q1EASY1.1 Scalars and Vectors1.1 标量与矢量No Calculator
Which pair lists one scalar and one vector, in that order?下列哪组依次列出了一个标量和一个矢量?
A car starts from rest and accelerates uniformly to $20~\mathrm{m/s}$ over $5~\mathrm{s}$. The distance it travels in this interval is一辆汽车从静止出发,在 $5~\mathrm{s}$ 内匀加速至 $20~\mathrm{m/s}$。该过程中行驶的路程为
(A) $25~\mathrm{m}$
(B) $50~\mathrm{m}$
(C) $75~\mathrm{m}$
(D) $100~\mathrm{m}$
Q6MEDIUM1.3 Free Fall1.3 自由落体No Calculator
A ball is dropped from rest from a height $H$ above level ground. Air resistance is negligible. Its speed just before impact is一只球从距水平地面高度 $H$ 处由静止释放,空气阻力不计。其落地前瞬间的速率为
A particle has acceleration $a(t) = 6t~\mathrm{m/s^2}$ and starts from rest at $x=0$. Its position at $t=2~\mathrm{s}$ is一质点的加速度为 $a(t) = 6t~\mathrm{m/s^2}$,从 $x=0$ 处由静止开始运动。其在 $t=2~\mathrm{s}$ 时的位置为
(A) $4~\mathrm{m}$
(B) $8~\mathrm{m}$
(C) $12~\mathrm{m}$
(D) $24~\mathrm{m}$
Q8MEDIUM1.4 Relative Motion1.4 相对运动No Calculator
A boat heads due north across a river at $4~\mathrm{m/s}$ relative to the water. The river flows due east at $3~\mathrm{m/s}$. The boat's speed relative to the bank is一艘船相对于水以 $4~\mathrm{m/s}$ 的速度正北方向横渡河流,河流以 $3~\mathrm{m/s}$ 向正东方流动。船相对于河岸的速率为
(A) $1~\mathrm{m/s}$
(B) $5~\mathrm{m/s}$
(C) $7~\mathrm{m/s}$
(D) $\sqrt{7}~\mathrm{m/s}$
Q9MEDIUM1.5 Projectile Motion1.5 抛体运动Calculator
A ball is launched from ground level with initial speed $25~\mathrm{m/s}$ at $40^\circ$ above the horizontal. Take $g=9.8~\mathrm{m/s^2}$. Its time of flight (return to launch height) is closest to一只球以 $25~\mathrm{m/s}$ 的初速度从地面以仰角 $40^\circ$ 抛出,取 $g=9.8~\mathrm{m/s^2}$。其飞行时间(回到发射高度所需时间)最接近
A projectile is launched from ground level with speed $v_0$ at angle $\theta$. Neglect air resistance. Its horizontal range is maximized when $\theta$ equals一抛体以速度 $v_0$、仰角 $\theta$ 从地面发射,不计空气阻力。当 $\theta$ 等于多少时水平射程最大?
(A) $30^\circ$
(B) $45^\circ$
(C) $60^\circ$
(D) $90^\circ$
Q11HARD1.2 Average vs. Instantaneous1.2 平均速度与瞬时速度No Calculator
A particle's position is $x(t)=t^3 - 6t^2 + 9t$ (SI). On the interval $0 \le t \le 4~\mathrm{s}$, the particle's average velocity equals its instantaneous velocity at $t=$质点的位置为 $x(t)=t^3 - 6t^2 + 9t$(SI 单位)。在区间 $0 \le t \le 4~\mathrm{s}$ 上,质点的平均速度等于其瞬时速度时,$t=$
(A) $1~\mathrm{s}$ only(仅此)
(B) $2~\mathrm{s}$ only(仅此)
(C) $2 \pm \dfrac{2\sqrt{3}}{3}~\mathrm{s}$
(D) $2 \pm \dfrac{\sqrt{3}}{3}~\mathrm{s}$
Q12HARD1.3 Free Fall + Reaction1.3 自由落体与反应Calculator
A stone is thrown straight up from the edge of a $40~\mathrm{m}$ cliff with initial speed $15~\mathrm{m/s}$. Take $g=9.8~\mathrm{m/s^2}$ and ignore air resistance. The stone's speed when it strikes the ground at the cliff's base is closest to一块石头以 $15~\mathrm{m/s}$ 的初速度从 $40~\mathrm{m}$ 高的悬崖边缘竖直向上抛出,取 $g=9.8~\mathrm{m/s^2}$,忽略空气阻力。石头落到崖底时的速率最接近
(A) $19~\mathrm{m/s}$
(B) $23~\mathrm{m/s}$
(C) $32~\mathrm{m/s}$
(D) $43~\mathrm{m/s}$
Q13HARD1.5 2-D Motion1.5 二维运动No Calculator
A particle moves in the $xy$-plane with $\vec r(t) = (3t)\,\hat\imath + (4t - t^2)\,\hat\jmath$ (SI). Its speed at $t=1~\mathrm{s}$ is一质点在 $xy$ 平面内运动,其位置矢量为 $\vec r(t) = (3t)\,\hat\imath + (4t - t^2)\,\hat\jmath$(SI 单位)。其在 $t=1~\mathrm{s}$ 时的速率为
A particle's $a$ vs. $t$ graph is a triangle: $a$ rises linearly from $0$ at $t=0$ to $a_0$ at $t=T/2$, then falls linearly back to $0$ at $t=T$. If the particle starts from rest, its speed at $t=T$ is一质点的 $a$-$t$ 图像为三角形:加速度从 $t=0$ 时的 $0$ 线性增大至 $t=T/2$ 时的 $a_0$,再线性减小至 $t=T$ 时的 $0$。若质点从静止出发,其在 $t=T$ 时的速率为
(A) $\dfrac{a_0 T}{4}$
(B) $\dfrac{a_0 T}{2}$
(C) $a_0 T$
(D) $\dfrac{a_0 T^2}{2}$
Q15EASY1.4 Relative Motion1.4 相对运动No Calculator
A train moves due east at $20~\mathrm{m/s}$ relative to the ground. A passenger walks toward the front of the train at $1.5~\mathrm{m/s}$ relative to the train. The passenger's velocity relative to the ground is一列火车相对于地面以 $20~\mathrm{m/s}$ 向正东方行驶。一位乘客相对于火车以 $1.5~\mathrm{m/s}$ 向车头方向行走。该乘客相对于地面的速度为
A particle moves along the $x$-axis with velocity $v(t) > 0$ that is decreasing in time. Which statement best describes the motion?一质点沿 $x$ 轴运动,其速度 $v(t) > 0$ 且随时间减小。下列哪个说法最能描述该运动?
(A)The particle is moving in the $+x$ direction and speeding up.质点沿 $+x$ 方向运动且速率增大。
(B)The particle is moving in the $+x$ direction and slowing down.质点沿 $+x$ 方向运动且速率减小。
(C)The particle is moving in the $-x$ direction and speeding up.质点沿 $-x$ 方向运动且速率增大。
From the same height above level ground, ball A is dropped from rest at the same instant ball B is launched horizontally. Air resistance is negligible. Which ball lands first?球 A 从同一高度由静止释放,同时球 B 从同一高度水平抛出,空气阻力不计。哪个球先落地?
(A)Ball A (dropped)球 A(自由落体)
(B)Ball B (horizontal)球 B(水平抛出)
(C)They land simultaneously.两球同时落地。
(D)Depends on ball B's horizontal speed.取决于球 B 的水平速度。
Q18HARD1.5 Projectile + Energy1.5 抛体与能量Calculator
A projectile is launched horizontally from a cliff of height $h$ with initial speed $v_0$. Air resistance is negligible. Its speed at the moment of impact is一抛体以初速度 $v_0$ 从高度为 $h$ 的悬崖顶端水平抛出,空气阻力不计。其落地瞬间的速率为
Show all work in the space provided. Partial credit is awarded for correct setup, units, and reasoning. Use $g=9.8~\mathrm{m/s^2}$ unless otherwise stated.请在所给空白处写出完整解题过程。正确的建模、单位及推理均可获得部分分值。除非另有说明,取 $g=9.8~\mathrm{m/s^2}$。
A particle moves along a straight line with acceleration $a(t) = 6 - 2t~\mathrm{(m/s^2)}$. At $t=0$, the particle is at $x=0$ with velocity $v_0 = 0$.一质点沿直线运动,其加速度为 $a(t) = 6 - 2t~\mathrm{(m/s^2)}$。在 $t=0$ 时,质点位于 $x=0$,初速度 $v_0 = 0$。
(a)Derive expressions for $v(t)$ and $x(t)$.推导 $v(t)$ 和 $x(t)$ 的表达式。
(b)At what time(s) is $v(t) = 0$? Justify whether the particle changes direction at any of these times.在哪些时刻 $v(t) = 0$?论证质点在这些时刻是否改变运动方向。
(c)Find the particle's maximum speed on $0 \le t \le 5~\mathrm{s}$ and the time at which it occurs.求质点在 $0 \le t \le 5~\mathrm{s}$ 内的最大速率及其发生的时刻。
(d)Compute the total distance traveled (not displacement) on $0 \le t \le 5~\mathrm{s}$.计算质点在 $0 \le t \le 5~\mathrm{s}$ 内的总路程(非位移)。
A projectile is launched from the edge of a cliff of height $h = 30~\mathrm{m}$ with an initial speed $v_0 = 22~\mathrm{m/s}$ at an angle $\theta = 35^\circ$ above the horizontal. Air resistance is negligible.一抛体以初速度 $v_0 = 22~\mathrm{m/s}$、仰角 $\theta = 35^\circ$ 从高 $h = 30~\mathrm{m}$ 的悬崖边缘发射,空气阻力不计。
(a)Resolve $\vec v_0$ into components and write the kinematic equations for $x(t)$ and $y(t)$, taking the launch point as the origin and $+y$ upward.将 $\vec v_0$ 分解为分量,并以发射点为原点、$+y$ 向上,写出 $x(t)$ 和 $y(t)$ 的运动学方程。
(b)Find the time at which the projectile reaches its maximum height. Compute the maximum height above the launch point.求抛体到达最高点的时刻,并计算相对于发射点的最大高度。
(c)Find the time at which the projectile lands on the ground at the base of the cliff.求抛体落到悬崖底部地面的时刻。
(d)Compute the horizontal range (measured from the launch point) and the speed at impact.计算水平射程(从发射点量起)及落地时的速率。
FRQ 3HARD1.4 Relative Motion1.4 相对运动Calculator
A river flows due east at $u = 2.0~\mathrm{m/s}$ in a region $L = 80~\mathrm{m}$ wide. A swimmer can swim at $v = 1.5~\mathrm{m/s}$ relative to the water. The swimmer enters at the south bank.一条河宽 $L = 80~\mathrm{m}$,河水以 $u = 2.0~\mathrm{m/s}$ 向正东方流动。一名游泳者相对于水的游速为 $v = 1.5~\mathrm{m/s}$,从南岸入水。
(a)If the swimmer aims due north (perpendicular to the flow), how long does it take to cross? How far downstream do they land?若游泳者正北方向(垂直于水流)游进,横渡需要多长时间?落点在下游多远处?
(b)Determine whether the swimmer can reach a point on the north bank directly across from their entry point. If so, give the heading angle (measured from north). If not, explain why and give the heading that minimizes downstream drift.判断游泳者能否到达对岸正对入水点的位置。若能,给出航向角(从正北量起);若不能,说明原因并给出使下游漂移最小的航向。
(c)For the heading from part (b), the one that minimizes drift, compute the downstream distance and the crossing time.对于 (b) 中使漂移最小的航向,计算下游漂移距离和横渡时间。
FRQ 4HARD1.2 / 1.3 Data + Calculus1.2 / 1.3 数据与微积分Calculator
A cart on a track is released and its position is recorded with a motion sensor:一辆小车在轨道上释放,运动传感器记录其位置如下:
$t$ (s)
0.0
0.2
0.4
0.6
0.8
1.0
$x$ (m)
0.00
0.04
0.16
0.36
0.64
1.00
(a)Show that the data are consistent with constant acceleration. Determine the value of the acceleration.证明数据符合匀加速运动。确定加速度的值。
(b)Estimate the cart's instantaneous velocity at $t = 0.5~\mathrm{s}$ using a centered-difference approximation, and compare with the prediction from part (a).用中心差分近似估算小车在 $t = 0.5~\mathrm{s}$ 时的瞬时速度,并与 (a) 中的预测值比较。
(c)The student claims that doubling the track tilt would double the acceleration. State whether this claim is consistent with constant-$a$ kinematics alone or whether it requires a dynamics argument. Justify briefly.该学生声称将轨道倾角翻倍会使加速度翻倍。说明此结论仅凭匀加速运动学是否成立,还是需要引入动力学论证。简要说明理由。