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Chapter 4 · Mechanics第4章 · 力学

Linear Momentum线动量

AP-Style Practice QuestionsAP 风格练习题

EASY MEDIUM HARD

Topics考点 4.1 - 4.4MECH



Name:姓名:Period:班级:
PART ITopics 4.1 - 4.4考点 4.1 - 4.4

Multiple Choice Questions选择题

Show all supporting work on scratch paper. Each item is labeled with its Mechanics topic and whether a calculator is permitted on that AP Exam section. Take $g = 9.8~\mathrm{m/s^2}$ unless a problem says otherwise.请在草稿纸上写出所有辅助步骤。每题均标注力学考点及该 AP 考试模块是否允许使用计算器。除题目另有说明外,取 $g = 9.8~\mathrm{m/s^2}$。

Q1EASY 4.1 Linear Momentum4.1 线动量No Calculator

A $0.50~\mathrm{kg}$ ball travels east at $4.0~\mathrm{m/s}$. The magnitude of its momentum is一个质量为 $0.50~\mathrm{kg}$ 的小球以 $4.0~\mathrm{m/s}$ 的速度向东运动。其动量大小为

Q2EASY 4.2 Impulse4.2 冲量No Calculator

A constant force of $10~\mathrm{N}$ acts on an object for $3.0~\mathrm{s}$. The magnitude of the impulse delivered to the object is一个 $10~\mathrm{N}$ 的恒力作用在某物体上,持续时间为 $3.0~\mathrm{s}$。该力对物体施加的冲量大小为

Q3EASY 4.3 Conservation of Momentum4.3 动量守恒No Calculator

Two carts of equal mass sit at rest on a frictionless track, in contact with a compressed spring between them. After the spring is released, cart A moves left at $2.0~\mathrm{m/s}$. Cart B then moves两辆质量相等的小车静止在无摩擦轨道上,中间夹着一根压缩弹簧。弹簧释放后,小车 A 以 $2.0~\mathrm{m/s}$ 向左运动,则小车 B 的运动情况为

Q4EASY 4.4 Inelastic vs. Elastic4.4 非弹性碰撞与弹性碰撞No Calculator

In which type of collision is the total kinetic energy of the system not conserved?在哪种碰撞类型中,系统的总动能守恒?

Q5MEDIUM 4.2 Impulse from $F$-$t$ Graph4.2 由 $F$-$t$ 图求冲量No Calculator

A force exerted on a $2.0~\mathrm{kg}$ object varies linearly from $0$ at $t = 0$ to $20~\mathrm{N}$ at $t = 0.40~\mathrm{s}$, then drops back to $0$ at $t = 0.80~\mathrm{s}$ (a triangular pulse). The object starts at rest. Its speed at $t = 0.80~\mathrm{s}$ is作用在 $2.0~\mathrm{kg}$ 物体上的力从 $t = 0$ 时的 $0$ 线性增大到 $t = 0.40~\mathrm{s}$ 时的 $20~\mathrm{N}$,再降回 $t = 0.80~\mathrm{s}$ 时的 $0$(三角脉冲)。物体由静止开始,$t = 0.80~\mathrm{s}$ 时的速度大小为

Q6MEDIUM 4.2 Vector Change in Momentum4.2 动量的矢量变化No Calculator

A $0.20~\mathrm{kg}$ ball strikes a wall horizontally at $5.0~\mathrm{m/s}$ and rebounds straight back at $4.0~\mathrm{m/s}$. The magnitude of the impulse delivered by the wall to the ball is一个 $0.20~\mathrm{kg}$ 的小球以 $5.0~\mathrm{m/s}$ 水平撞墙,以 $4.0~\mathrm{m/s}$ 原路反弹。墙壁对小球施加的冲量大小为

Q7MEDIUM 4.4 Perfectly Inelastic Collision4.4 完全非弹性碰撞No Calculator

A $3.0~\mathrm{kg}$ cart moving at $4.0~\mathrm{m/s}$ collides with and sticks to a stationary $1.0~\mathrm{kg}$ cart on a frictionless track. The speed of the combined carts immediately after the collision is一辆质量为 $3.0~\mathrm{kg}$ 、速度为 $4.0~\mathrm{m/s}$ 的小车在无摩擦轨道上与静止的 $1.0~\mathrm{kg}$ 小车碰撞并粘在一起。碰后两车合体的速度大小为

Q8MEDIUM 4.3 Recoil4.3 反冲No Calculator

A $60~\mathrm{kg}$ skater stands at rest on frictionless ice and throws a $3.0~\mathrm{kg}$ ball horizontally at $8.0~\mathrm{m/s}$ relative to the ground. The skater's recoil speed is一名 $60~\mathrm{kg}$ 的溜冰者静止站在无摩擦冰面上,水平抛出一个 $3.0~\mathrm{kg}$ 的球,球相对地面的速度为 $8.0~\mathrm{m/s}$。溜冰者的反冲速度大小为

Q9MEDIUM 4.4 Equal-Mass Elastic Collision4.4 等质量弹性碰撞No Calculator

In a one-dimensional elastic collision, a moving puck strikes an identical stationary puck. Immediately after the collision,在一维弹性碰撞中,一个运动的冰球撞击一个相同质量且静止的冰球。碰撞后瞬间,

Q10MEDIUM 4.3 Two-Dimensional Conservation4.3 二维动量守恒No Calculator

Two pucks of equal mass collide and stick together. Just before the collision, puck 1 moves east at $3.0~\mathrm{m/s}$ and puck 2 moves north at $4.0~\mathrm{m/s}$. Immediately after the collision, the speed of the combined object is两个质量相等的冰球碰撞后粘在一起。碰前,冰球 1 以 $3.0~\mathrm{m/s}$ 向东运动,冰球 2 以 $4.0~\mathrm{m/s}$ 向北运动。碰后合体的速度大小为

Q11MEDIUM 4.2 Average Force4.2 平均力Calculator

A $0.15~\mathrm{kg}$ baseball arrives at home plate moving horizontally at $40~\mathrm{m/s}$ and is hit straight back at $50~\mathrm{m/s}$. The contact between bat and ball lasts $1.5~\mathrm{ms}$. The magnitude of the average force exerted by the bat on the ball is closest to一个 $0.15~\mathrm{kg}$ 的棒球以 $40~\mathrm{m/s}$ 水平飞向本垒板,被击后以 $50~\mathrm{m/s}$ 原路返回。球棒与球的接触时间为 $1.5~\mathrm{ms}$。球棒对球施加的平均力大小最接近

Q12MEDIUM 4.4 KE Before vs. After4.4 碰撞前后动能比较No Calculator

Two carts of equal mass collide head-on at the same speed and stick together. Compared with the total kinetic energy before the collision, the total kinetic energy immediately after the collision is两辆质量相等的小车以相同速度正面碰撞并粘在一起。与碰前总动能相比,碰后瞬间的总动能为

Q13MEDIUM 4.1 Momentum as a Vector4.1 动量的矢量性No Calculator

Object X has mass $2m$ and moves east at speed $v$. Object Y has mass $m$ and moves north at speed $2v$. The magnitudes of the two momentum vectors satisfy物体 X 质量为 $2m$,以速度 $v$ 向东运动;物体 Y 质量为 $m$,以速度 $2v$ 向北运动。两动量向量大小满足

Q14HARD 4.4 Unequal-Mass Elastic Collision4.4 不等质量弹性碰撞No Calculator

A puck of mass $M$ moves at speed $v$ and undergoes a one-dimensional elastic collision with a stationary puck of mass $3M$. Immediately after the collision, the velocities of the incoming and target pucks are, respectively,质量为 $M$ 的冰球以速度 $v$ 运动,与质量为 $3M$ 的静止冰球发生一维弹性碰撞。碰后瞬间,入射冰球和目标冰球的速度分别为

Q15HARD 4.3 Ballistic Pendulum4.3 弹道摆Calculator

A $0.020~\mathrm{kg}$ bullet moving horizontally at $300~\mathrm{m/s}$ strikes and embeds itself in a $2.98~\mathrm{kg}$ block hanging at rest at the end of a long string. Take $g = 9.8~\mathrm{m/s^2}$. The maximum height (above the lowest point of the swing) reached by the block-plus-bullet is closest to一颗质量为 $0.020~\mathrm{kg}$ 的子弹以 $300~\mathrm{m/s}$ 水平飞行,嵌入悬挂在长绳末端静止的 $2.98~\mathrm{kg}$ 木块中。取 $g = 9.8~\mathrm{m/s^2}$,木块加子弹摆动到的最大高度(相对摆动最低点)最接近

Q16HARD 4.4 Two-Dimensional Elastic Collision4.4 二维弹性碰撞No Calculator

Two pucks of equal mass $m$ undergo an elastic collision on a frictionless surface. Puck 1 moves east at speed $v$ and strikes puck 2, which is at rest. After the collision, puck 1 moves at $60^\circ$ north of east with speed $v/2$. The speed of puck 2 immediately after the collision is两个质量均为 $m$ 的冰球在无摩擦表面上发生弹性碰撞。冰球 1 以速度 $v$ 向东运动并撞击静止的冰球 2。碰后,冰球 1 以速度 $v/2$ 沿东偏北 $60^\circ$ 方向运动。碰后瞬间冰球 2 的速度大小为

Q17HARD 4.2 Variable-Force Impulse4.2 变力冲量No Calculator

A particle of mass $m$ initially at rest experiences a force $F(t) = \alpha t$ (with $\alpha$ a positive constant) along the $+x$ direction from $t = 0$ to $t = T$. The particle's speed at $t = T$ is质量为 $m$ 的质点由静止开始,在 $t = 0$ 到 $t = T$ 期间受到沿 $+x$ 方向的力 $F(t) = \alpha t$($\alpha$ 为正常数)。$t = T$ 时质点的速度大小为

Q18HARD 4.4 Fraction of KE Lost4.4 动能损失比例No Calculator

A projectile of mass $m$ moving at speed $v$ collides perfectly inelastically with a stationary target of mass $M$. The fraction of the projectile's original kinetic energy that is dissipated (converted to heat, sound, deformation, etc.) is质量为 $m$、速度为 $v$ 的抛射体与质量为 $M$ 的静止靶体发生完全非弹性碰撞。抛射体原有动能中被耗散(转化为热能、声能、形变能等)的比例为

PART IIFree-Response · Topics 4.1 - 4.4自由作答 · 考点 4.1 - 4.4

Free-Response Questions自由作答题

Show all work in the space provided. Partial credit is awarded for correct setup, units, and reasoning. Use $g = 9.8~\mathrm{m/s^2}$ unless otherwise stated.请在给定空间内写出完整解题过程。正确的建立方程、单位和推理均可获得部分得分。除题目另有说明外,取 $g = 9.8~\mathrm{m/s^2}$。

FRQ 1MEDIUM 4.2 Variable-Force Impulse4.2 变力冲量Calculator

A horizontal force $F(t) = \alpha\,t$, with $\alpha = 24~\mathrm{N/s}$, acts along the $+x$ direction on a $0.50~\mathrm{kg}$ block that is initially at rest on a frictionless surface, from $t = 0$ to $t = 0.50~\mathrm{s}$.水平力 $F(t) = \alpha\,t$($\alpha = 24~\mathrm{N/s}$)沿 $+x$ 方向作用在初始静止于无摩擦表面上的 $0.50~\mathrm{kg}$ 滑块上,时间从 $t = 0$ 到 $t = 0.50~\mathrm{s}$。

(a) Set up an integral expression for the impulse delivered to the block from $t = 0$ to $t = 0.50~\mathrm{s}$, and evaluate it.建立从 $t = 0$ 到 $t = 0.50~\mathrm{s}$ 冲量的积分表达式并求值。
(b) Determine the speed of the block at $t = 0.50~\mathrm{s}$.求滑块在 $t = 0.50~\mathrm{s}$ 时的速度大小。
(c) Determine the average force exerted on the block over this interval, and compare it with the peak instantaneous force.求该时间段内作用在滑块上的平均力,并与峰值瞬时力进行比较。
(d) The same impulse is now to be delivered as a constant force over a shorter interval of $0.10~\mathrm{s}$. Determine the magnitude of that constant force, and explain qualitatively why "spreading the impulse out over a longer time" is preferred for things like air bags or padded dashboards.现将相同的冲量以恒力形式在较短的 $0.10~\mathrm{s}$ 内施加。求该恒力的大小,并定性解释为何"将冲量分散在较长时间内"更适用于安全气囊或软质仪表板等场合。
FRQ 2MEDIUM 4.3 Recoil & Center of Mass4.3 反冲与质心Calculator

A $60~\mathrm{kg}$ skater holding a $4.0~\mathrm{kg}$ medicine ball stands at rest on frictionless ice. She throws the ball horizontally so that the ball moves at $6.0~\mathrm{m/s}$ relative to the ground.一名持有 $4.0~\mathrm{kg}$ 实心球的 $60~\mathrm{kg}$ 溜冰者静止站在无摩擦冰面上。她水平抛出该球,使其相对地面的速度为 $6.0~\mathrm{m/s}$。

(a) Determine the skater's recoil velocity (magnitude and direction).求溜冰者的反冲速度(大小与方向)。
(b) Verify explicitly that the total momentum of the skater-plus-ball system is conserved.明确验证溜冰者加球系统的总动量守恒。
(c) Determine the total kinetic energy of the system after the throw, and explain where this energy came from.求抛球后系统的总动能,并解释该能量的来源。
(d) Suppose instead the skater throws the ball at $6.0~\mathrm{m/s}$ measured in her own frame (i.e. relative to herself). Set up and solve for her recoil velocity in this case. (Note: this is a different problem, the lab-frame ball speed is no longer $6.0~\mathrm{m/s}$.)若溜冰者改为以相对于自身参考系(即相对于自己)$6.0~\mathrm{m/s}$ 抛出球,建立方程并求此情况下她的反冲速度。(注:这是不同的情形,实验室参考系中球速不再是 $6.0~\mathrm{m/s}$。)
FRQ 3HARD 4.4 1-D Elastic Collision4.4 一维弹性碰撞Calculator

A puck of mass $m_1 = 0.30~\mathrm{kg}$ moves to the right at $v_1 = 4.0~\mathrm{m/s}$ and collides head-on elastically with a puck of mass $m_2 = 0.10~\mathrm{kg}$ moving to the left at $v_2 = 2.0~\mathrm{m/s}$.质量为 $m_1 = 0.30~\mathrm{kg}$ 的冰球以 $v_1 = 4.0~\mathrm{m/s}$ 向右运动,与质量为 $m_2 = 0.10~\mathrm{kg}$、以 $v_2 = 2.0~\mathrm{m/s}$ 向左运动的冰球正面弹性碰撞。

(a) Write the conservation-of-momentum and conservation-of-kinetic-energy equations for this collision in terms of the unknowns $v_1'$ and $v_2'$.以未知量 $v_1'$ 和 $v_2'$ 写出该碰撞的动量守恒方程和动能守恒方程。
(b) Solve the equations from (a) for $v_1'$ and $v_2'$. (You may use the standard 1-D elastic-collision result, but justify it.)由 (a) 中方程求解 $v_1'$ 和 $v_2'$。(可使用标准一维弹性碰撞结果,但需给出依据。)
(c) Compute the kinetic energy of each puck before and after the collision and verify that the total is conserved.计算碰前和碰后每个冰球的动能,并验证总动能守恒。
(d) Determine the velocity of the center of mass of the two-puck system, and explain why it is unchanged by the collision.求两冰球系统质心的速度,并解释为何碰撞不改变质心速度。
FRQ 4HARD 4.4 2-D Collision4.4 二维碰撞Calculator

A $2.0~\mathrm{kg}$ puck moving east at $5.0~\mathrm{m/s}$ collides on frictionless ice with a $3.0~\mathrm{kg}$ puck initially at rest. After the collision, the $2.0~\mathrm{kg}$ puck moves at $30^\circ$ north of east with a speed of $2.0~\mathrm{m/s}$.一个 $2.0~\mathrm{kg}$ 的冰球以 $5.0~\mathrm{m/s}$ 向东运动,在无摩擦冰面上与初始静止的 $3.0~\mathrm{kg}$ 冰球碰撞。碰后,$2.0~\mathrm{kg}$ 冰球以 $2.0~\mathrm{m/s}$ 的速度沿东偏北 $30^\circ$ 方向运动。

(a) Apply conservation of momentum component-wise to determine the $x$- and $y$-components of the $3.0~\mathrm{kg}$ puck's velocity after the collision.对动量守恒分量求解,求 $3.0~\mathrm{kg}$ 冰球碰后速度的 $x$ 分量和 $y$ 分量。
(b) Determine the speed and direction of the $3.0~\mathrm{kg}$ puck after the collision.求碰后 $3.0~\mathrm{kg}$ 冰球的速度大小与方向。
(c) Compute the total kinetic energy of the system before and after the collision. Determine whether the collision is elastic or inelastic; if inelastic, find the fraction of the initial kinetic energy that was lost.计算碰前和碰后系统的总动能。判断碰撞是弹性还是非弹性;若为非弹性,求初始动能损失的比例。
(d) Determine the velocity of the center of mass of the system both before and after the collision and confirm it is unchanged.求碰前和碰后系统质心的速度,并验证其不变。